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____ [38]
3 years ago
9

What did rutherford discover that thomson did not understand?

Chemistry
1 answer:
user100 [1]3 years ago
6 0

Answer:

the answer is D

Explanation:

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Consider a mixture of NaCl and NaNO3 that is 31.8% Na by mass. Calculate the percentage by mass of NaCl in the mixture.
lutik1710 [3]

<u>Answer:</u> The percentage by mass of NaCl in the mixture is 38.5 %

<u>Explanation:</u>

To calculate the mass percentage of element in compound, we use the equation:

\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100      .......(1)

  • <u>For NaCl:</u>

Mass of sodium element = 23 g

Mass of NaCl = 58.5 g

Putting values in equation 1, we get:

\text{Mass percent of sodium element}=\frac{23g}{58.5g}\times 100=39.32\%

Mass fraction of sodium metal in NaCl = 0.3932

  • <u>For NaNO_3 :</u>

Mass of sodium element = 23 g

Mass of NaNO_3 = 85 g

Putting values in equation 1, we get:

\text{Mass percent of sodium element}=\frac{23g}{85g}\times 100=27.1\%

Mass fraction of sodium metal in sodium nitrate = 0.271

Let us assume the mass fraction of NaCl in the mixture is 'x'

So, the mass fraction of NaNO_3 in the mixture will be '(1-x)'

We are given:

Percent by mass of Na in the mixture = 31.8 %

Mass fraction of Na in the mixture = 0.318

Evaluating the mass fraction of NaCl in the mixture:

[(x\times 0.3932)+((1-x)\times 0.271)]=0.318

x = 0.385

Percent by mass of NaCl in the mixture will be = (0.385\times 100)=38.5\%

Hence, the percentage by mass of NaCl in the mixture is 38.5 %

4 0
3 years ago
You place a mass of 250 grams on the measurement tray of a triple beam balance and then set the rider on the 500 gram beam to th
Gala2k [10]

Answer:

  • <u>The pointer will not be lined up with the zero mark; it will be above the zero mark.</u>

Explanation:

Althoug the list of statements is not provided, you can assure that the pointer will not be lined up with the zero mark, but above the zero mark.

A <em>triple beam balance</em> is very precise instrument, of common use in most labs, used to measure masses. It has three beams. Each beam works for different precisions and mass increments. One beam measures 1 g increments, other beam measures 10 g increments, and the other one 100 g increments.

If you place a mass of 250 grams on the measurement tray, then the weight will be balanced in the beams with 200 grams in the beam that reads increments of 100 g and 50 grams in the beam that reads increments of 10 g. When this is the situation, the weight is completely balanced, and the pointer will be lined up with the zero mark. But this is not the case.

When the rider on the 500 gram beam is set to the 200 gram mark, and the other riders are set to 0 grams, the weight of the mass (250 g) on the tray is greater than the force exerted by the rider on the beam (200 g) and so the tray will be below the level of balance, and the beam will be above the level of balance. The level of balance is indicated when the pointer is lined up with the zero mark.

7 0
3 years ago
Why does oxygen have a melting point
Jlenok [28]

Answer:

The intermolecular forces between water molecules are stronger than those between oxygen molecules. In general, the bigger the molecule, the stronger the intermolecular forces, so the higher the melting and boiling points.

5 0
3 years ago
Read 2 more answers
What is the product when 3,3-dimethyl-1-butanol undergoes oxidation
Step2247 [10]

The compound given (i.e. 3,3-dimethyl-1-butanol) is primary alcohol (1°) because the functional group (-OH) shows that it is alcohol is attached to a primary carbon (i.e terminal carbon).

The oxidation of all primary alcohols results in the formation of aliphatic aldehyde(also known as alkanal).

Suppose, it is secondary alcohol;

The oxidation of secondary alcohol results in the formation of ketone(also known as alkanone).

When  3,3-dimethyl-1-butanol undergoes oxidation, the suffix "ol" in the alcohol changes to "al"

Therefore,  3,3-dimethyl-1-butanol changes to  3,3-dimethyl-1-butanal after undergoing oxidation.

In conclusion, the product when 3,3-dimethyl-1-butanol undergoes oxidation is: 3,3-dimethylbutanal.

As such, option  2 is correct.

Learn more about oxidation reaction here:

brainly.com/question/14863344?referrer=searchResults

3 0
3 years ago
Which of the following are examples of destructive forces?
Masja [62]
C) both ice and wind
3 0
3 years ago
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