Answer:
1) Maximun ammount of nitrogen gas: ![m_{N2}=10.682 g N_2](https://tex.z-dn.net/?f=m_%7BN2%7D%3D10.682%20g%20N_2)
2) Limiting reagent: ![NO](https://tex.z-dn.net/?f=NO)
3) Ammount of excess reagent: ![m_{N2}=4.274 g](https://tex.z-dn.net/?f=m_%7BN2%7D%3D4.274%20g)
Explanation:
<u>The reaction </u>
![2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)](https://tex.z-dn.net/?f=2%20NO%20%28g%29%20%2B%202%20H_2%20%28g%29%20%5Clongrightarrow%20N_2%20%28g%29%20%2B%202%20H_2O%20%28g%29)
Moles of nitrogen monoxide
Molecular weight: ![M_{NO}=30 g/mol](https://tex.z-dn.net/?f=M_%7BNO%7D%3D30%20g%2Fmol)
![n_{NO}=\frac{m_{NO}}{M_{NO}}](https://tex.z-dn.net/?f=n_%7BNO%7D%3D%5Cfrac%7Bm_%7BNO%7D%7D%7BM_%7BNO%7D%7D)
![n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol](https://tex.z-dn.net/?f=n_%7BNO%7D%3D%5Cfrac%7B22.9%20g%7D%7B30%20g%2Fmol%7D%3D0.763%20mol)
Moles of hydrogen
Molecular weight: ![M_{H2}=2 g/mol](https://tex.z-dn.net/?f=M_%7BH2%7D%3D2%20g%2Fmol)
![n_{H2}=\frac{m_{H2}}{M_{H2}}](https://tex.z-dn.net/?f=n_%7BH2%7D%3D%5Cfrac%7Bm_%7BH2%7D%7D%7BM_%7BH2%7D%7D)
![n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol](https://tex.z-dn.net/?f=n_%7BH2%7D%3D%5Cfrac%7B.5.8%20g%7D%7B2%20g%2Fmol%7D%3D2.9%20mol)
Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess
1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted
![m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}](https://tex.z-dn.net/?f=m_%7BN2%7D%3D0.763%20mol%20NO%2A%20%5Cfrac%7B1%20mol%20N_2%7D%7B2%20mol%20NO%7D%2A%5Cfrac%7B28%20g%20N_2%7D%7Bmol%20N_2%7D)
![m_{N2}=10.682 g N_2](https://tex.z-dn.net/?f=m_%7BN2%7D%3D10.682%20g%20N_2)
2) <u>Limiting reagent</u>:
3) <u>Ammount of excess reagent</u>:
![m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}](https://tex.z-dn.net/?f=m_%7BN2%7D%3D%282.9%20mol%20-%200.763%20mol%20NO%2A%20%5Cfrac%7B1%20mol%20H_2%7D%7B1%20mol%20NO%7D%29%2A%5Cfrac%7B2%20g%20H_2%7D%7Bmol%20H_2%7D)
![m_{N2}=4.274 g](https://tex.z-dn.net/?f=m_%7BN2%7D%3D4.274%20g)
Answer:
The relation between the shielding and effective nuclear charge is given as
![Z_{eff} = Z -S](https://tex.z-dn.net/?f=Z_%7Beff%7D%20%3D%20Z%20-S)
where s denote shielding
z_{eff} denote effective nuclear charge
Z - atomic number
Explanation:
shielding is referred to as the repulsion of an outermost electron to the pull of electron from valence shell. Higher the electron in valence shell higher will be the shielding effects.
Effective nuclear charge is the amount of net positive charge that valence electron has.
The relation between the shielding and the effective nuclear charge is given as
wheres denote shielding
z_{eff} denote effective nuclear charge
Z - atomic number
In my opinion the answer is D
Answer : The correct option is, Mass
Explanation :
As we know that there are 3 states of matter :
Solid state : It is a state in which the particles are closely packed and does not have any space between them. This state have a definite shape and volume.
Liquid state : It is a state in which the particles are present in random and irregular pattern. The particles are closely arranged but they can move from one place to another. This state have a definite volume but does not have a fixed shape.
Gaseous state : It is a state in which the particles are loosely arranged and have a lot of space between them. This state have indefinite volume as well as shape.
If we are taking 100 grams of ice then after melting its mass remains same but its shape, volume and temperature will be changed and after evaporation its mass remains same but its shape, volume and temperature will be changed.
Hence, the mass will stay constant, no matter if the substance is in the solid, liquid, or gas state.