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Lady_Fox [76]
4 years ago
15

Pls pls I need help to solve this questions

Chemistry
1 answer:
cupoosta [38]4 years ago
6 0
1) • Solubility is the ability of a substance to be dissolved especially in water
• Unit; mg/L (milligrams per liter)

2) A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent.

3) To detoxify any acid that was previously used in it

4) CAN’T SEE THE MAIN QUESTIONS

5) CAN’T SEE THE MAIN QUESTIONS
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What the definition of each period and group and element and every valence electron
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SCIENCE:how can i model a ice cream maker melting!?
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3 years ago
To maximize the yield in a certain manufacturing process, a solution of a weak monoprotic acid that has a concentration between
stira [4]

Answer: C 115 ml

Explanation:

If you have a solution of a monoprotic acid, it means that it has the form HA (just one Hydrigen atom). Therefore, one molecule of acid is going to react with just one molecule of  NaOH.

So, if you have a solution of 100 ml of 0,2 HA acid, it is going to react with a 100 ml of 0,2 M NaOH solution. Beacause we know that the acid can be a little more concentrated than 0,2 M (0,2-0,3), it probably needs a little more than 100 ml of NaOH to react.  So, the answer is C.

in 100 ml of 0,2M acid you can find 0,002 mol of HA

in 100 ml of 0,3 M acid you can find 0,003 mol of HA

in 100 ml of 0,2 M NaOH you can find 0,002 mol of NaOH

the answer can not be 200 because in 200 ml of 0,2 M NaOH there are 0,004 mol of NaOH, which is more than 0,003 mol.

0 0
3 years ago
Excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide to produce aqueous sodium nitrate and copper(II) sulfide as
nikitadnepr [17]

The question in incomplete, complete question is;

Determine the theoretical yield:

Excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide to produce aqueous sodium nitrate and copper(II) sulfide as a precipitate. In this reaction 469 grams of copper(II) nitrate were combined with 156 grams of sodium sulfide to produce 272 grams of sodium nitrate.

Answer:

The theoretical yield of sodium nitrate is 340 grams.

Explanation:

Cu(NO_3)_2(aq)+Na_2S(aq)\rightarrow 2NaNO_3(aq)+CuS(s)

Moles of copper(II) nitrate = \frac{469 g}{187.5 g/mol}=2.5013 mol

Moles of sodium sulfide = \frac{156 g}{78 g/mol}=2 mol

According to reaction, 1 mole of copper (II) nitrate reacts with 1 mole of sodium sulfide.

Then 2 moles of sodium sulfide will react with:

\frac{1}{1}\times 2mol= 2 mol of copper (II) nitrate

As we can see from this sodium sulfide is present in limiting amount, so the amount of sodium nitrate will depend upon moles of sodium sulfide.

According to reaction, 1 mole of sodium sulfide gives 2 mole of sodium nitrate, then 2 mole of sodium sulfide will give:

\frac{2}{1}\times 2mol=4 mol sodium nitrate

Mass of 4 moles of sodium nitrate :

85 g/mol × 4 mol = 340 g

Theoretical yield of sodium nitrate = 340 g

The theoretical yield of sodium nitrate is 340 grams.

7 0
3 years ago
Read 2 more answers
Please help!!! I can’t figure it out!
marin [14]

Answer:

The third answer

Explanation:

6 0
3 years ago
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