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Firdavs [7]
4 years ago
6

Given the following unbalanced thermochemical equation, how much heat will be released from the combustion of 45.5 grams of CH4

in an excess of oxygen gas? CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) + 890 kJ
Chemistry
1 answer:
AnnyKZ [126]4 years ago
8 0

CH4 + 2O2 → CO2 + 2H2O + 890 kJ

MM of CH4 = (12.01 + 4x1.008) g/mol = 16.04 g/mol

Moles of CH4 = 45.5 g CH4 x (1 mol CH4/16.04 g CH4) = 2.837 mol CH4

q = 2.837 mol CH4 x (890 kJ/1 mol CH4) = 2520 kJ

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Can a non-polar molecule contain polar bonds? Explain your answer with an example.
Rom4ik [11]

Answer:

Yes

Explanation:

It is possible that a non polar molecule contain polar bonds.

Consider the example of CO₂:

In carbon dioxide the atoms are arranged in angle of 180 degree and molecule is linear. So in this way the net dipole movement becomes zero and molecule is non polar.

But when we see the electronegativity of both bonded atoms the oxygen is more electronegative than carbon. The oxygen atom have partial negative charge and carbon have partial positive charge because shared pair of electron is more attracted towards the oxygen. Thus bond become polar because one end is partial positive and other is partial negative. Thus a non polar carbon dioxide molecule have polar bond.

8 0
3 years ago
What is the total amount of work done when Danny lifted 25 pounds of weight over 5 meters and applying 30- Newtons of Force? ​
MariettaO [177]

Answer:

Definition and Mathematics of Work

Calculating the Amount of Work Done by Forces

Potential Energy

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5 0
3 years ago
What mass of K2CO3 is needed to prepare 200. mL of a solution having a potassium ion concentration of 0.150 M
I am Lyosha [343]

<u>Answer:</u>

2.07 grams

<u>Explanation:</u>

We know that the molecular mass of K_2CO_3 is 138.205 grams.

In order to find out how many grams we need to make 200 mL having a potassium ion concentration of 0.150, we need to find the number of moles first.

M = moles / liters

0.150 = x / 0.200

x = 0.03 moles

Since there are 2 potassium atoms in each molecule of K_2CO_3 so we will divide this number by half and multiply it by the molecular mass.

0.03/2 = 0.015 moles

Mass of K_2CO_3 needed = 0.015 × 138.205 = 2.07 grams

4 0
3 years ago
ASAP PLEASEE A certain amount of Argon has 2.4x10^24 atoms. Going backwards from Atoms to Grams, how many grams of Ar would that
Dima020 [189]

The required mass of argon in given number of atoms of argon is 155.61 grams.

<h3>What is Avogadro's number?</h3>

Avogadro's number is the number of atoms which are present in 1 mole of any substance and it is equal to 6.022×10²³.

Relation between the mass and moles of any substance will be represented as:

  • n = W/M, where
  • W = given mass
  • M = molar mass

So, moles of argon will be calculated by using given number of atoms as:

Moles = 2.4×10²⁴ atoms / 6.022×10²³ atoms per mole

Moles = 3.9 moles

Now mass will be:

W = (3.9mol)(39.9g/mol) = 155.61 g

Hence required mass of argon is 155.6g.

To know more about Avogadro's number, visit the below link:

brainly.com/question/1513182

#SPJ1

8 0
2 years ago
this is liquid water in the form of droplets that have condoned from atmospheric water vapor and than precipitated
svetlana [45]
I think it’s rain???
6 0
3 years ago
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