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SVEN [57.7K]
3 years ago
10

Never mind i got it hahahaha

Chemistry
2 answers:
Ipatiy [6.2K]3 years ago
6 0

Answer:eeee

Explanation:

pshichka [43]3 years ago
5 0

Answer:

Congrats I am so happy for you! You rock it!

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Water a combination of the elements hydrogen and oxygen, is an example of an
marin [14]

Answer:

Explanation:

Common Examples of the Law of Definite Proportions

Water, written as the chemical compound H20, is made up of atoms of hydrogen and oxygen. If one oxygen atom is combined with two hydrogen atoms, water is created.

3 0
3 years ago
How many molecules are in 3.6 grams of NaCl?
raketka [301]

Answer:

\boxed{\text{None}}

Explanation:

There are no molecules in NaCl, because it consists only of ions.

However, we can calculate the number of formula units (FU) of NaCl.

Step 1. Calculate the moles of NaCl

\text{No. of moles}=\text{3.6 g NaCl}\times \dfrac{\text{1 mol NaCl}}{\text{63.54 g NaCl}} = \text{0.0567 mol NaCl}

Step 2. Convert moles to formula units

\text{FU} = \text{0.0567 mol NaCl} \times \dfrac{6.022 \times 10^{23}\text{ FU NaCl}}{\text{1 mol NaCl}}\\\\= 3.4 \times 10^{22} \text{ FU NaCl}

There are \boxed{3.4 \times 10^{22} \text{ FU NaCl}} in 3.6 g of NaCl.

6 0
3 years ago
The oxidation number of all the element in free state is 0​
Art [367]

Answer:

Zero-Nine

Explanation:

this is becasue these numbers are rather small and if you plug these numbers into an equation you will most likely get 0.

8 0
3 years ago
1. A neutral atom of fluorine (F) has 9 electrons and an electron configuration of 1s2 2s2 2p5. How will it ionize to achieve an
Natasha2012 [34]
These answers dont make sense

1. the 2s2 orbital will give one of its electrons to the 2p5 orbital so the configuration would be 1s22s12p6 (2s1 is half filled and 2p6 is completely filled which is a much more stable configuration)

2. Neon does not need to ionize it is a noble gas
4 0
3 years ago
Given the following: [G3P] = 1.5x10-5M; [BPG] = 3.0x10-3M ; [NAD+] = 1.2x10-5M; [NADH]=1.0x10-4 ; [HPO42-]= 1.2x10-5 M; pH = 7.5
mel-nik [20]

<u>Answer:</u> The given reaction is non-spontaneous in nature.

<u>Explanation:</u>

To calculate the H^+ concentration, we use the equation:

pH=-\log[H^+]

We are given:

pH of the solution = 7.5

7.5=-\log [H^+]

[H^+]=10^{-7.5)=3.1\times 10^{-8}M

For the given chemical equation:

\text{Glyceraldehyde3-phosphate }+NAD^++HPO_4^{2-}\rightarrow \text{1,3-Biphosphoglycerate }+NADH+H^+

The equation used to Gibbs free energy of the reaction follows:

\Delta G=\Delta G^o+RT\ln K_{eq}

where,

\Delta G = free energy of the reaction

\Delta G^o = standard Gibbs free energy = 6.3 kJ/mol = 6300 J/mol  (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

T = Temperature = 25^oC=[273+25]K=298K  

K_{eq} = Ratio of concentration of products and reactants = \frac{[BPG][NaDH][H^+]}{[G_3P][NAD^+][HPO_4^{2-}]}

[BPG]=3.0\times 10^{-3}M

[NADH]=1.0\times 10^{-4}M

[H^+]=3.1\times 10^{-8}M

[G_3P]=1.5\times 10^{-5}M

[NAD^+]=1.2\times 10^{-5}M

[HPO_4^{2-}]=1.2\times 10^{-5}M

Putting values in above equation, we get:

\Delta G=6300J/mol+(8.314J/K.mol\times 298K\times \ln (\frac{(3.0\times 10^{-3})\times (1.0\times 10^{-4})\times (3.1\times 10^{-8})}{(1.5\times 10^{-5})\times (1.2\times 10^{-5})\times (1.2\times 10^{-5})}))\\\\\Delta G=9917.02J/mol=9.92kJ/mol

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

As, the Gibbs free energy of the reaction is positive. The reaction is said to be non-spontaneous.

Hence, the given reaction is non-spontaneous in nature.

4 0
3 years ago
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