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4 years ago

According to einstein's general theory of relativity, why does light take a curved path when passing near a galaxy?

1 answer:

3 0

According to general relativity, objects by the virtue of their mass have the ability to disrupt spacetime around them. This disruption in spacetime is actually what we call gravity.

So light always travels in a straight path in spacetime but because spacetime is now bent, the path appears to be curved in space

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What is the distance to a star whose parallex is 0.1 sec?

Arte-miy333 [17]

Answer:

$30.86\times 10^{13} km$

Explanation:

Given the parallex of the star is 0.1 sec.

The distance is inversely related with the parallex of the star. Mathematically,

$d=\frac{1}{P}$

Here, d is the distance to a star which is measured in parsecs, and P is the parallex which is measured in arc seconds.

Now,

$d=\frac{1}{0.1}\\d=10 parsec$

And also know that,

$1 parsec=3.086\times 10^{13} km$

Therefore the distance of the star is $30.86\times 10^{13} km$ away.

6 0

3 years ago

How is most water in your body eliminated?

Drupady [299]

Answer:

your body loses water from the kidneys through the urine

6 0

3 years ago

Read 2 more answers

The mean diameters of planets A and B are 8.1 × 103 km and 1.4 × 104 km, respectively. The ratio of the mass of planet A to that

lisabon 2012 [21]

Answer:

dA/dB = 4.955

Approximately, the ratio is 5/1

(Where dA is mean density for planet A while dB is mean density for planet B)

Explanation:

Mass of A = mA

Mass of B = mB

mA/mB = 0.96

Mean radius for A = mA = (8.1 × 10^3)/2 = 4.05 × 10^3 km

Mean radius for B = mB = (1.4 × 10^4)/2

= 7×10^3km

Density = mass/volume

Volume of a sphere = 4/3Πr3

Mean volume for A = (4/3) × Π × (4.05 × 10^3)^3

= 2.784 × 10^11 km3

Mean volume for B = 4/3×Π×(7×10^3)^3

= 1.437 × 10^12km3

Since m/v = d ( where m = mass, v = volume and d = density)

mA = 2.784 × 10^11 km3 × dA ...equation 1

mB= 1.437 × 10^12km3 × dB... equation 2

but mA/mB= 0.96

mA = 0.96 × mB

substitute for mA in equation 1

0.96 × mB = 2.784 × 10^11 x dA equation 3

Substitute for mB in equation 3..

(refer to equation 2)

0.96×1.437×10^12 × dB = 2.784 × 10^11 × dA .....equation 4

divide through by the coefficient of dA

dA = (0.96×1.437×10^12×dB)/(2.784 × 10^11)

divide through by dB

dA/dB = 4.955

therefore, the ratio of dA to dB is 5/1

Therefore, the mean density of A is almost five times that of B

7 0

3 years ago

Given a 3.00 μF capacitor, a 7.75 μF capacitor, and a 5.00 V battery, find the charge on each capacitor if you connect them in t

USPshnik [31]

Answer:

a) Q1= Q2= 11.75×10^-6Coulombs

b) Q1 =15×10^-6coulombs

Q2 = 38.75×10^-6coulombs

Explanation:

a) For a series connected capacitors C1 and C2, their equivalent capacitance C is expressed as

1/Ct = 1/C1 + 1/C2

Given C1 = 3.00 μF C2 = 7.75μF

1/Ct = 1/3+1/7.73

1/Ct = 0.333+ 0.129

1/Ct = 0.462

Ct = 1/0.462

Ct = 2.35μF

V = 5.00Volts

To calculate the charge on each each capacitors, we use the formula Q = CtV where Cf is the total equivalent capacitance

Q = 2.35×10^-6× 5

Q = 11.75×10^-6Coulombs

Since same charge flows through a series connected capacitors, therefore Q1= Q2=

11.75×10^-6Coulombs

b) If the capacitors are connected in parallel, their equivalent capacitance will be C = C1+C2

C = 3.00 μF + 7.75 μF

C = 10.75 μF

For 3.00 μF capacitance, the charge on it will be Q1 = C1V

Q1 = 3×10^-6 × 5

Q1 =15×10^-6coulombs

For 7.75 μF capacitance, the charge on it will be Q2 = 7.75×10^-6×5

Q2 = 38.75×10^-6coulombs

Note that for a parallel connected capacitors, same voltage flows through them but different charge, hence the need to use the same value of the voltage for both capacitors.

7 0

3 years ago

Enter a curve slower than the posted speed if your vehicle has a high center of gravity or if surface _____________ is less than

alisha [4.7K]

Answer:

Traction

Explanation:

Enter a curve slower than the posted speed if your vehicle has a high center of gravity or if surface Traction is less than ideal.

Traction is an act of drawing or pulling something over a surface specially a road or a track or it also defined as the grip of a tire on road or a wheel on rail. So speed when entering a curve should be slower when the tire has low traction to avoid accident.

5 0

3 years ago