The distance traveled by the sprinter in meters is determined as 1.88 m.
<h3>Acceleration of the sprinter</h3>
The acceleration of the sprinter is the rate of change of velocity of the sprinter with time.
The acceleration of the sprinter is calculated as follows;
Apply Newton's second law of motion as follows;
F = ma
a = F/m
where;
- F is the applied force by the sprinter
- m is mass of the sprinter
- a is acceleration of the sprinter
a = 693 N / 64 kg
a = 10.83 m/s²
<h3>Distance traveled by the sprinter</h3>
The distance traveled by the sprinter is calculated as follows;
s = ut + ¹/₂at²
where;
- u is initial velocity = 0
s = ¹/₂at²
where;
- t is time of motion
- a is acceleration
s = (0.5)(10.83)(0.59²)
s = 1.88 m
Thus, the distance traveled by the sprinter in meters is determined as 1.88 m.
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Answer:
Gamma rays is the correct answer.
Explanation:
Answer:
distance or displacement
Explanation:
the answer can be displacement or displacement. if the required measure is between two points, we can call it as distance. but if we are to find the distance moved, we call it displacement. though it sounds pretty similar, they are very different. displacement is the shortest distance of movement of a body to its final point (or to the asked point) and distance is the total distance travelled by the body. and while distance is a scalar quantity, that this value shows the magnitude, displacement is a vector quantity, that this value should show both magnitude and direction.
for example if an object travels from point A to point B that is a 10 meters away and back, the distance will be 10+10 which is 20 meters. but the displacement is 0!
since not much information is given, the answer can be both distance or displacement
Conducting plates will be 3.75 m apart if an electric field strength of 4. 4 kV/m between them, if their potential difference is 15 kV
The potential difference, also referred to as voltage difference between two given points is the work in joules required to move one coulomb of charge from one point to the other. The SI unit of voltage is the volt. Volt Formula.
In a simple parallel-plate capacitor, a voltage applied between two conductive plates creates a uniform electric field between those plates. The electric field strength in a capacitor is directly proportional to the voltage applied and inversely proportional to the distance between the plates.
E = V/d
E = Electric field strength
d = distance between the plates
V = potential difference
Electric field strength = 4 kV/m
Potential difference = 15 kV
d = V / E = 15 kV / 4 kV/m
= 3.75 m
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