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expeople1 [14]
3 years ago
8

A cardboard box sits on top of a concrete sidewalk where the coefficient of friction between the surfaces is 0.4. The mass of th

e box is 10 Kg and the box is pulled horizontally with a force of 60 N. What is the Gravitational Force on the box? What is the Normal Force? What is the Frictional Force? What is the Acceleration?

Physics
1 answer:
Sloan [31]3 years ago
6 0

Answer:

Fg = 98.1 [N]; N = 98.1 [N]; Ff = 39.24 [N]; a = 2.076[m/^2]

Explanation:

To solve this problem, we must make a free body diagram and interpret each of the forces acting on the box. In the attached diagram we can find the free body diagram.

The gravitational force is equal to:

Fg = (10 * 9.81) = 98.1 [N]

Now by summing forces on the Y axis equal to zero, we can find the normal force exerted by the surface.

N - Fg = 0

N = Fg

N = 98.1 [N]

The friction force is defined as the product of normal force by the coefficient of friction.

Ff = N * μ

Ff = 98.1 * 0.4

Ff = 39.24 [N]

By the sum forces on the x-axis equal to the product of mass by acceleration (newton's second law), we can find the value of acceleration.

60 - Ff = m * a

60 - 39.24 = 10 * a

a = 2.076[m/^2]

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Answer:

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Explanation:

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Moreover, the force is:

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In this problem:

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If a 400-mm diameter pipe with a pipe roughness coefficient of 100 flows full of pressurized water with a head loss of 0.4 ft pe
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Answer:

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Explanation:

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P = Friction Loss per foot of pipe = \frac{0.4}{1000\ ft} = 4 x 10⁻⁴

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Therefore,

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A bird flies at a speed of 2.3 m/s if it has 14 j of kinetic energy what is the mass
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14  =      1/2 * m* 2.3²

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Mass = 5.29 kg.
7 0
3 years ago
Read 2 more answers
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