Answer : T = 2 s and Speed = 6.28 m/s.
Explanation :
It is given that,
Mass of the ball, m = 10 kg
Radius of the circle, r = 2 m
The ball makes 30 revolutions per minute. So, frequency is given by :


We know that time period is defined as the reciprocal of frequency i.e.


So, the time period for the ball to go around once is 2 s.
Now, speed is defined as distance travelled per unit time. Distance travelled by ball in circular path is equal to the circumference of the circle.




Speed of the ball is 6.28 m/s.
The gravitational force between the objects is 
Explanation:
The magnitude of the gravitational force between two objects is given by the equation:
where
is the gravitational constant
are the masses of the two objects
r is the separation between the objects
For the two objects in this problem:

And their distance is
r = 2.6 m
So, the gravitational force between them is

Learn more about gravitational force:
brainly.com/question/1724648
brainly.com/question/12785992
#LearnwithBrainly
Answer:
Explanation:
1 gal = 231 in³
231 in³ (2.54³ cm³/in³) = 3,785.411784 cm³
3,785.411784 cm³ (0.01³ m³/cm³) = 0.003785411784 m³
0.003785411784 m³ / 25 m² = 0.00015141647136 m
or approximately 0.15 mm
Answer:
3.83×10¯⁴ N
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = +2.4x10¯⁸ C
Charge 2 (q₂) = +1.8x10¯⁶ C
Distance apart (r) = 1.008 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Force (F) =?
The magnitude of the electrical force acting between the two charges can be obtained as follow:
F = Kq₁q₂ / r²
F = 9×10⁹ × 2.4x10¯⁸ × 1.8x10¯⁶ / (1.008)²
F = 0.0003888 / 1.016064
F = 3.83×10¯⁴ N
Thus the magnitude of the electrical force acting between the two charges is 3.83×10¯⁴ N