Larger. How big depends on the size of the vector. But think about pythagoras theorem to solve for the vector.
<span>Hey there!
Awesome question=)
Siobhan can place it on a regular scale(0 gravity area), or she can use the "balance scale"
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I hope this helps;)
Answer: It will fall short of its goal.
Explanation: I took the quiz.
Answer:
The acceleration of the sprinter is 1.4 m/s²
Explanation:
Hi there!
The equation of position of the sprinter is the following:
x = x0 + v0 · t + 1/2 · a · t²
Where:
x = position of the sprinter at a time t.
x0 = initial position.
v0 = initial velocity.
t = time.
a = acceleration.
Since the origin of the frame of reference is located at the starting point and the sprinter starts from rest, then, x0 and v0 are equal to zero:
x = 1/2 · a · t²
At t = 9.9 s, x = 71 m
71 m = 1/2 · a · (9.9 s)²
2 · 71 m / (9.9 s)² = a
a = 1.4 m/s²
The acceleration of the sprinter is 1.4 m/s²
Answer:
to absorb extra light- E.
