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arlik [135]
2 years ago
12

How many moles of Carbon are in 3.06 g of Carbon

Chemistry
1 answer:
natta225 [31]2 years ago
3 0

Answer:

\boxed {\boxed {\sf 0.255 \ mol \ C }}

Explanation:

If we want to convert from grams to moles, the molar mass is used. This is the mass of 1 mole. They are found on the Periodic Table as the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

Look up the molar mass of carbon.

  • Carbon (C): 12.011 g/mol

Set up a ratio using the molar mass.

\frac {12.011 \ g \ C}{ 1 \ mol \ C}

Since we are converting 3.06 grams to moles, we multiply by that value.

3.06 \ g \ C*\frac {12.011 \ g \ C}{ 1 \ mol \ C}

Flip the ratio. This way, the ratio is still equivalent, but the units of grams of carbon cancel.

3.06 \ g \ C* \frac{1 \ mol \ C}{12.011 \ g\ C}                      

3.06 * \frac{1 \ mol \ C}{12.011 }    

\frac {3.06}{12.011 } \ mol \ C                                

0.25476646 \ mol \ C

The original measurement of grams (3.06) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

  • 0.25476646

The 7 in the ten-thousandth place tells us to round the 4 up to a 5.

0.255 \ mol \ C

3.06 grams of carbon is approximately <u>0.255 moles of carbon.</u>

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grigory [225]
[H+] in first brand:
4.5 = -log([H+])
[H+] = 10^(-4.5)

[H+] in second brand:
5 = -log[H+]
[H+] = 10^(-5)

Difference = 10^(-4.5) - 10^(-5)
= 2.2 x 10⁻⁵

The answer is A.
7 0
3 years ago
Read 2 more answers
18. What is the percent by mass sugar of a solution made by dissolving 12.45 grams of sugar in 100 grams of water?
Fantom [35]

The percent by mass sugar of a solution : 11.07%

<h3>Further explanation</h3>

Given

mass of sugar = 12.45 g

mass of water = 100 g

Required

The percent by mass

Solution

Mass of solution :

\tt mass~sugar+mass~water=12.45+100=112.45~g

Percent mass of sugar :

\tt \%mass=\dfrac{mass~sugar}{mass~solution}\times 100\%\\\\\%mass=\dfrac{12.45}{112.45}\times 100\%=11.07\%

6 0
2 years ago
If 22.5L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at constant temperature. What is the new volume?2.A gas with a vol
kykrilka [37]

Answer:

a)23.2 L

b)68.3kPa

c)7.5 atm

d)60.5L

e)1.67 atm

Explanation:

From Boyle's law:

P1V1=P2V2

P1= 748mmHg

P2=725mmHg

V1= 22.5L

V2??

V2= P1V1/P2= 748×22.5/725= 23.2 L

b)

V1=4.0L

P1= 205×10^3Pa

V2= 12.0L

P2=???

P2= P1V1/V2= 205×10^3×4/12

P2= 68.3×10^3 Pa or 68.3kPa

c)

P1= 1 atm

V1= 196.0L

P2= ??

V2= 26.0L

P2= P1V1/V2=1×196.0/26.0

P2= 7.5 atm

d)

V1= 40.0L

P1= 12.7×10^3Pa

V2=???

P2= 8.4×103Pa

V2= P1V1/P2= 12.7×10^3×40.0/8.4×103

V2=60.5L

e)

V1= 100mL

P1= 1atm

V2= 60mL

P2=???

P2= P1V1/V2= 1×100/60

P2= 1.67 atm

4 0
3 years ago
How many liters of salt solution will be needed to provide 15 grams of salt if the concentration of the solution is 50 g/l?​
asambeis [7]

Answer:

.30 l

Explanation:

15g/50g/l= .3l

6 0
2 years ago
A certain chemical reaction releases 31.0 kj/g of heat for each gram of reactant consumed. How can you calculate what mass of re
Aleksandr-060686 [28]

Answer:

See explanation.

Explanation:

Hello!

In this case, since we know the heat of reaction per gram of reactant and we should know the total energy of reaction, but it is not there, we are going to assume it is 1200 J as usual in these problems, so you can change it to whatever your given heat is.

In such a way, we set up the math as shown below:

m= 1200J*\frac{1kJ}{1000J}*\frac{1g}{31.0kJ}

Which results:

m=0.0387g

Best regards!

7 0
3 years ago
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