This is what i got in the caculator 6400 if not im so so sory
Answer:
Step-by-step explanation:
-8×+40>-16
<h3>Rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr</h3><h3><u>Solution:</u></h3>
Given that,
A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream
Therefore,
Upstream distance = 165 km
Upstream time = 3 hours
<h3><u>Find upstream speed:</u></h3>

Thus upstream speed is 55 km per hour
Downstream distance = 510 km
Downstream time = 6 hours
<h3><u>Find downstream speed:</u></h3>

Thus downstream speed is 85 km per hour
<em><u>If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then</u></em>
Speed downstream = u + v km/hr
Speed upstream = u - v km/hr
Therefore,
u + v = 85 ----- eqn 1
u - v = 55 ----- eqn 2
Solve both
Add them
u + v + u - v = 85 + 55
2u = 140
u = 70
<em><u>Substitute u = 70 in eqn 1</u></em>
70 + v = 85
v = 85 - 70
v = 15
Thus rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr
Answer:
The answer to that question is c. y = x
Answer:
Tn = 6.4 + 1.8n
Step-by-step explanation:
Given
Sequence: 8.2, 10, 11.8, 13.6
Required
The formula of the sequence.
First, the type of the sequence needs to be determined (arithmetic or geometric)
It is an arithmetic sequence because each successive sequence is separated by a common difference..
The common difference is represented by d and it's calculated as follows.
d = 10 - 8.2 or 11.8 - 10 or 13.6 - 11.8
Each of the above gives
d = 1.8
Now, that we have the common difference; the next is to determine the formula using the Arithmetic Progression formula.
Tn = T1 + (n - 1)d
Where T1 is the first term of the progression; T1 = 8.2
By substituting 8.2 for T1 and 1.8 for d.
This gives
Tn = 8.2 + (n - 1) * 1.8
Open bracket
Tn = 8.2 + 1.8 * n - 1 * 1.8
Tn = 8.2 + 1.8n - 1.8
Collect like terms
Tn = 8.2 - 1.8 + 1.8n
Tn = 6.4 + 1.8n
Hence, the formula of the sequence is Tn = 6.4 + 1.8n