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Stolb23 [73]
3 years ago
13

a 320-foot tree casts a 130-foot shadow on horizontal ground. a girl lying on the grass at the tip of the shadow is looking at a

bird nesting at the top of the tree. at what angle is the girl looking up? assume that the tree grows at a right angle to the ground g

Physics
1 answer:
mixer [17]3 years ago
7 0

Answer:\theta =67.88^{\circ}

Explanation:

Given

Height of tree is H=320 ft

length of shadow L=130 ft

let \theta be the angle of elevation

using trigonometric relation

\tan \theta =\frac{H}{L}

\tan \theta =\frac{320}{130}

\theta =tan^{-1}(2.461)

\theta =67.88^{\circ}

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Mumz [18]
I’m pretty sure it’s average speed= total distance and total time which is A.
3 0
3 years ago
Which of the following is an example of an endothermic reaction?
il63 [147K]

Answer:

D, photosynthesis

Explanation:

6 0
3 years ago
Read 2 more answers
A cyclist starts at rest and accelerates at 0.5 m/s2 south for 20 s. What is the cyclist’s final velocity
inn [45]

The cyclist's final velocity is 10 m/s.

From the question,

We are to determine the cyclist's final velocity.

<h3>Linear motion</h3>

From one of the equations of motion for linear motion, we have

v=u+at

Where

v is the final velocity

u is the initial velocity

a is the acceleration

and t is the time

From the given information,

The cyclist starts at rest, this means the initial velocity is 0 m/s

That is,

u = 0 m/s

Also

a = 0.5 m/s²

and t = 20 s

Putting the parameters into the equation, we get

v = 0 + 0.5 \times 20

v = 0 + 10

v = 10 \ m/s

Hence, the cyclist's final velocity is 10 m/s.

Learn more on linear motion here: brainly.com/question/19365526

8 0
2 years ago
A plastic rod has been bent into a circle of radius R = 8.00 cm. It has a charge Q1 = +2.70 pC uniformly distributed along one-q
vovikov84 [41]

Answer:

Part a)

V = -1.52 V

Part b)

V = -1.16 V

Explanation:

Part a)

Electric potential is a scalar quantity

so here we can say that total potential due to a ring on its center is given as

V = \frac{kQ}{R}

here we know that

Q = Q_1 - 6Q_1

Q = - 5 Q_1

Q_1 = 2.70 pC

now we have

V = \frac{(9\times 10^9)(-5\times 2.70 \times 10^{-12})}{0.08}

V = -1.52 V

Part b)

Potential on the axis of the ring is given as

V = \frac{kQ}{\sqrt{r^2 + R^2}}

V = \frac{(9\times 10^9)(-5\times 2.70\times 10^{-12})}{\sqrt{0.08^2 + 0.0671^2}}

V = -1.16 V

8 0
3 years ago
When a golfer tees off, the head of her golf club, which has a mass of 160 g, is traveling 50 m/s just before it strikes a 46 g
olya-2409 [2.1K]

Answer:

v1=21.81m/s

Explanation:

<em>When a golfer tees off, the head of her golf club, which has a mass of 160 g, is traveling 50 m/s just before it strikes a 46 g golf ball at rest on a tee. Immediately after the collision, the club head continues to travel in the same direction but at a reduced speed of 44 m/s. Neglect the mass of the club handle and determine the speed (in m/s) of the golf ball just after impact.</em>

According to the law of conservation of momentum, if the net external force on a system is zero, then the linear momentum of the system is conserved.

During collision of two particles, the external force on the system of two colliding particles is zero (only internal force acts between the colliding particles), therefore, the momentum is conserved during the collision.

Answer and Explanation:

Given :

head of the golf club=160g

velocity of the golf club=50 m/s

golf ball mass=46g

velocity=om/s

m1u1+m2u2=m1v1+m2v2.........................................1

160*50 +46*0=160*44+46*v1

8000=7040+46v1

960=46v1

v1=960/46

v1=21.81m/s

3 0
3 years ago
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