<h2>
The seagull's approximate height above the ground at the time the clam was dropped is 4 m</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Time, t = 3 s
Substituting
s = ut + 0.5 at²
s = 0 x 3 + 0.5 x 9.81 x 3²
s = 44.145 m
The seagull's approximate height above the ground at the time the clam was dropped is 4 m
C :) cause a direction has nothing do do with velocity !
The correct answer for that question would be. A
Answer:
A. 0 m/s
Explanation:
The rest frame of an object is defined as the reference frame that is moving together with the object, so at the same speed of the object.
In other words, the rest frame of an object is defined as the reference frame in which the object is at rest, which means that is the reference frame in which the object has speed equal to zero (0 m/s).
Therefore, the correct answer is
A. 0 m/s
Answer:
The fire hose be located 59.80 m away to hit the highest possible fire.
Explanation:
Vertical velocity = 25 sin35 = 14.34 m/s
Acceleration = -9.81m/s²
At maximum height , final vertical velocity = 0 m/s
We have v = u + at
Substituting
0 = 14.34 - 9.81 x t
t = 1.46 s
Time of flight of water = 2 x 1.46 = 2.92 s
Horizontal velocity = 25 cos35 = 20.48 m/s
Horizontal displacement = 20.48 x 2.92 = 59.80 m
So, the fire hose be located 59.80 m away to hit the highest possible fire.
