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Kitty [74]
3 years ago
15

) A 1.0kW kettle contains 500g of boiling waterCalculate the time needed to evaporate all the water

Physics
1 answer:
Doss [256]3 years ago
4 0

Answer:

t = 1130 s = 18.83 min

Explanation:

First, we will calculate the energy required to evaporate 500 g of water:

E = mL

where,

E = Energy Required for evaporation of water =?

m = mass of water = 500 g = 0.5 kg

L = Latent heat of vaporization of water = 2.26 MJ/kg = 2260 KJ/kg

Therefore,

E = (0.5\ kg)(2260\ KJ/kg)\\E = 1130\ KJ

Now, we will calculate the time required:

P = \frac{W}{t}\\\\t = \frac{W}{P}

where,

t = time = ?

P = Power of kettle = 1 KW

Therefore,

t = \frac{1130\ KJ}{1 KW}\\\\

<u>t = 1130 s = 18.83 min</u>

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