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Gwar [14]
3 years ago
11

Suppose that the process were repeated, except that in step 3 a neutral acrylic rod instead of a finger is used to touch the ele

ctroscope's post, which is then removed in step 4. How would this modification affect the experiment just described? Select all correct statements The net charge on the vane would change following step 3, but revert to its original value following step 4. The net charge on the vane in all steps would be exactly as it was when the experimenter used a finger. The net charge on the vane would not change as a consequence of step 3. The net charge on the vane + post + disk would be zero for all steps. The net charge on the vane following steps 3 through 5 would have a sign opposite what it was when the experimenter used a finger.
Physics
1 answer:
Marta_Voda [28]3 years ago
8 0

Answer:

b) True Only if the finger is isolated from ground

c) True. The total charge does not change since the system is isolated

Explanation:

When the electroscope is touched with an acrylic rod, some charges are transferred from the electroscope to the rod, until the charge in both is equal.

In the case it know when the electroscope is touched with a finger, two things can happen.

- The body is isolated from the ground, the efective charge is redistributed between the two bodies. Case similar to insulating rod

- The body is connected to ground, the charge is transferred to the finger and from here to the ground until the total charge is transferred and the Earth and the final charge of the electroscope is zero.

Let's review the final statements

a) False, when part of the load is touched, it passes to the rod, so when it separates it does not return to the initial load

b) True Only if the finger is isolated from ground

c) True. The total load does not change since the system is isolated

d) False. The value of the load changes =, but its sign does not

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Two metal spheres are suspended from strings. The
nikdorinn [45]

Answer:

B. A repulsive force of 8.0*10^3 N.

Explanation:

As we know by Coulomb's law that the electrostatic force between two charges is given as

F = \frac{kq_1q_2}{r^2}

here we know that

q_1 = -2 \times 10^2 C

q_2 = -4 \times 10^{-8} C

r = 3.0 m

now we have

F = \frac{(9 \times 10^9)(2 \times 10^2)(4\times 10^{-8})}{3^2}

F = 8000 N

since both charges are similar charges so they will repel each other by the force we calculated above so correct answer will be

B. A repulsive force of 8.0*10^3 N.

3 0
3 years ago
A cardinal (Richmondena cardinalis) of mass 3.70×10−2 kg and a baseball of mass 0.144 kg have the same kinetic energy. What is t
Radda [10]

Answer:

\frac{p_{c}}{p_{b}}\approx 0.507

Explanation:

Since the cardinal and ball have the same kinetic energy, it is possible to determine the ratio between speeds. (c for cardinal, b for baseball)

K_{c} = K_{b}

\frac{1}{2}\cdot m_{c}\cdot v_{c}^{2}= \frac{1}{2}\cdot m_{b}\cdot v_{b}^{2}

\frac{v_{c}}{v_{b}}=\sqrt{\frac{m_{b}}{m_{c}} }

The ratio is obtained by multiplying each side by \frac{m_{c}}{m_{b}}:

\frac{p_{c}}{p_{b}}=\frac{m_{c}}{m_{b}}\cdot \sqrt{\frac{m_{b}}{m_{c}} }

\frac{p_{c}}{p_{b}}= \sqrt{\frac{m_{c}}{m_{b}} }

The value of this ratio is:

\frac{p_{c}}{p_{b}}\approx 0.507

3 0
3 years ago
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Why are renewable sources of energy better than nonrenewable sources?
Anton [14]
Because it does not produce waste, thus it doesn't harm the environment. also renewable sources are infinite.
5 0
3 years ago
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A 1200-kg car initially at rest undergoes constant acceleration for 8.8 s, reaching a speed of 10 m/ s. It then collides with a
atroni [7]

Answer:

The final kinetic energy of the two-car system is 60,000 J.

Explanation:

Given;

mass of the car, m = 1200 kg

time of motion, t = 8.8 s

final velocity of the car, v = 10 m/s

Apply the principle of conservation of kinetic energy; the initial kinetic energy is equal final kinetic energy.

K.E_i = K.E_f\\\\K.E_f = \frac{1}{2}mv^2\\\\K.E_f =  \frac{1}{2}(1200)(10)^2\\\\K.E_f = 60,000 \ J

Therefore, the final kinetic energy of the two-car system is 60,000 J.

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Convert 592 minutes to seconds. using one step conversion.
vovangra [49]

Answer:

35520

Explanation:

592 times 60=35520

8 0
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