Answer:
Explanation:
Hello, in this case, the lead is catching heat and the water losing it, that's why the heat relation ship is (D is for Δ):

Now, by stating the heat capacity definition:

Solving for the equilibrium temperature:

Which is very close to the water's temperature since the lead's both mass and head capacity are lower than those for water.
Best regards.
Answer:
The normal amount of disaccharide would be produced, but fewer monosaccharides would be produced.
Explanation:
The first reaction, the conversion of starch into disaccharides, is catalyzed by the enzyme amylase. <u>Since amylase is present in a normal amount, a normal amount of disaccharides will be produced.</u>
In the second reaction, these disaccharides will be transformed into monosaccharides by a disaccharidase. However, since t<u>here is less disaccharidase, there will be fewer monosaccharides produced than if it was a normal amount of amylase.</u>
NaHCO3 is the answer for the query
Answer: Thus the value of
is 110.25
Explanation:
Initial moles of
= 0.500 mole
Initial moles of
= 0.500 mole
Volume of container = 1 L
Initial concentration of
Initial concentration of
equilibrium concentration of
[/tex]
The given balanced equilibrium reaction is,

Initial conc. 0.500 M 0.500 M 0 M
At eqm. conc. (0.500-x) M (0.500-x) M (2x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[IBr]^2}{[Br_2]\times [I_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BIBr%5D%5E2%7D%7B%5BBr_2%5D%5Ctimes%20%5BI_2%5D%7D)

we are given : 2x = 0.84 M
x= 0.42
Now put all the given values in this expression, we get :


Thus the value of the equilibrium constant is 110.25
<u>Answer:</u> The solubility of ethylene gas in water is 
<u>Explanation:</u>
To calculate the molar solubility, we use the equation given by Henry's law, which is:

where,
= Henry's constant = 
= molar solubility of ethylene gas = ?
= partial pressure of ethylene gas = 0.684 atm
Putting values in above equation, we get:

Converting this into grams per liter, by multiplying with the molar mass of ethylene:
Molar mass of ethylene gas = 28 g/mol
So, 
Hence, the solubility of ethylene gas in water is 