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Sophie [7]
4 years ago
8

In CF4 and NF3, the ___electron groups on the central C and N atoms have a ___ arrangement. The shapes of the molecules are dete

rmined by the number of ___ of electrons: since CF4 has ___ bonded atom(s) and ___ lone pair(s) of electrons, the shape is ___. Since NF3 has ___ bonded atom(s) and ___ lone pair(s) of electrons, the shape is ___.
Chemistry
2 answers:
Jobisdone [24]4 years ago
8 0

Answer:

four

Tetrahedral

Pair

four

zero

tetrahedral

three

one

Trigonal Pyramidal

Explanation:

In CF4 and NF3, the four electron groups on the central C and N atoms have a Tetrahedral arrangement. The shapes of the molecules are determined by the number of pair of electrons: since CF4 has four bonded atom(s) and zero lone pair(s) of electrons, the shape is tetrahedral. Since NF3 has three bonded atom(s) and one lone pair(s) of electrons, the shape is trigonal pyramidal.

What we were told to do is to fill in the gaps whose answers have been provided.

enyata [817]4 years ago
7 0

Answer:

Explanation:

In CF4 and NF3, the valence electron groups on the central C and N atoms have a tetrahedral arrangement. The shapes of the molecules are determined by the number of bonding and nonbonding of electrons: since CF4 has four bonded atom(s) and zero lone pair(s) of electrons, the shape is tetrahedral.

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PLS HELP QUICK ALOTTT OF POINTS
timofeeve [1]

Answer:

\boxed {\boxed {\sf 0.80 \ mol\ F}}

Explanation:

We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.

We will convert using dimensional analysis and set up a ratio using Avogadro's Number.

\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}

We are converting 4.8 × 10²³ fluorine atoms to moles, so we multiply the ratio by this number.

4.8 \times 10^{23} \ atoms \ F *\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}

Flip the ratio so the units of atoms of fluorine cancel each other out.

4.8 \times 10^{23} \ atoms \ F *\frac { 1 \ mol \ F}{6.022 \times 10^{23} \ atoms \ F}

4.8 \times 10^{23}  *\frac { 1 \ mol \ F}{6.022 \times 10^{23} }

Condense into 1 fraction.

\frac { 4.8 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ F

Divide.

0.7970773829 \ mol \ F

The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we found, that is the hundredths place. The 7 in the thousandths tells us to round the 9 in the hundredths place up to a 0. Then, we also have to round the 7 in the tenths place up to an 8.

0.80 \ mol \ F

4.8 × 10²³ fluorine atoms are equal to <u>0.80 moles of fluorine.</u>

6 0
3 years ago
Why do actinides form covalent bond?​
Jet001 [13]

Answer:

bonding driven by ionic interactions.

Explanation:

5 0
2 years ago
Be able to identify the correct elements using clues such as numbers of protons,locations (family/period), number of neutrons, n
Brilliant_brown [7]

an element's name, chemical symbol, atomic number, atomic mass.

IDK what you are even asking for

6 0
3 years ago
2 bromocyclopentanamine structural formula
Elis [28]

Answer:

The structure is given in attached file.

Explanation:

Explanation

2-bromocyclopentamine (Figure attached) is a synthetic compound which is synthesized by substitution reaction of cyclopentamine and hydrobromide. Its molecular formula and molecular mass are C5H10NBr and 164.05 mol/g respectively.  It is a very reactive compound so it doesn’t available in pure form, it is present in market as a mixture of 2-bromocyclopentamine and Hydrobromide.

Properties :

Its boiling point is 115 0C

Its melting point is – 75 oC

It is highly flammable

It is highly toxic

It is irritant

It is corrosive in nature

5 0
3 years ago
UU
BigorU [14]

Answer:

Samarium

Explanation:

The element Sm describe is called Samarium. This element has unique sets of properties that makes it very unique and distinct.

The lanthanides are found in the f-block on the periodic table of elements.

This element is a moderately hard silvery metal that readily oxidizes in air. It assumes an oxidation state of +3. The element has an atomic number of 62

7 0
3 years ago
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