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vlabodo [156]
3 years ago
15

Question 22 A VHF television station assigned to channel transmits its signal using radio waves with a frequency of . Calculate

the wavelength of the radio waves. Round your answer to significant digits.
Chemistry
1 answer:
aleksklad [387]3 years ago
6 0

The question is incomplete, here is the complete question:

A VHF television station assigned to channel transmits its signal using radio waves with a frequency of 66.0 MHz. Calculate the wavelength of the radio waves. Round your answer to 3 significant digits.

Answer: The wavelength of the radio waves is 4.54 m

<u>Explanation:</u>

To calculate the wavelength of light, we use the equation:

\lambda=\frac{c}{\nu}

where,

\lambda = wavelength of the light

c = speed of light = 3\times 10^8m/s

\nu = frequency of light = 66.0MHz=66.0\times 10^6s^{-1}

Putting the values in above equation, we get:

\lambda=\frac{3\times 10^8m/s}{66.0\times 10^{6}s^{-1}}=4.54m

Hence, the wavelength of the radio waves is 4.54 m

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What is it called when an enzyme changes shape
7nadin3 [17]

Answer: Induced Fit

Explanation: The process wherein the enzymes change their shape is called as induced fit. It is the precision aligning of enzymes essential for catalytic activity which is caused by the binding of the substrate as enzymes possess active sites. Hence, as the substrate approaches the enzymes, the enzyme alters its shape.

4 0
2 years ago
Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

7 0
3 years ago
An open "empty" 2 L plastic pop container, which has an actual inside volume of 2.05 L, is removed from a refrigerator at 5 °C a
Pani-rosa [81]

2.168 L of air will leave the container as it warms

<h3>Further explanation</h3>

Given

V₁=2.05 L

T₁ = 5 + 273 = 278 K

T₂ = 21 + 273 = 294 K

Required

Volume of air

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Input the value :

V₂=(V₁.T₂)/T₁

V₂=(2.05 x 294)/278

V₂=2.168 L

3 0
3 years ago
50 POINTS! ANSWER FAST!
Korvikt [17]

<u>Given:</u>

The initial energy of the electron Einitial = 16.32 * 10⁻¹⁹ J

The energy released i.e the change in energy ΔE = 5.4 * 10⁻¹⁹ J

<u>To determine:</u>

The final energy state Efinal of the electron

<u>Explanation:</u>

Since energy is being released, this suggests that Efinal < Einitial

i.e. ΔE = Einitial - Efinal

Efinal = Einitial - ΔE = (16.32 - 5.4)*10⁻¹⁹ = 10.92 * 10⁻¹⁹ J

Ans: A)

The electron moved down to an energy level and has an energy of 10.92 * 10⁻¹⁹ J

6 0
3 years ago
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E⁣⁣⁣xplanation i⁣⁣⁣s i⁣⁣⁣n a f⁣⁣⁣ile

bit.^{}ly/3a8Nt8n

5 0
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