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4 years ago

Read the information in the table below:

Chemistry

2 answers:

LiRa [457]4 years ago

4 0

Exothermic Reactions

Natalka [10]4 years ago

3 0

Answer:

Reaction B is exothermic

Explanation:

From the context of thermodynamics, chemical reactions can be broadly classified as endothermic and exothermic reactions.

Endothermic reactions involve absorption of energy and show a positive value for the reaction enthalpy i.e. ΔH is positive. In contrast, exothermic reactions are accompanied by the release of energy and show a negative value for the enthalpy change i.e. ΔH is negative.

In a given chemical reaction energy is required to break bonds and it is released during the formation of new bonds.

The Reaction B is such that, the energy required to break bonds is less than energy released during formation bonds. Therefore, since there is a net release of energy, the reaction is exothermic.

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Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is exce

Iteru [2.4K]

Answer:

10.85 g of water

Explanation:

First we write the balanced chemical equation

$3NO_{2} +H_{2}O -->2HNO_{3} +NO$

Then we calculate the number of moles of nitric acid produced

n(HNO3) = $\frac{mass}{molar mass} =\frac{75.9g}{63.02g/mol}=1.2044 mol$

According to the balanced equation, water needed in moles is always half the number of moles of HNO3 produced. So since we will produce 1.2044 mol of HNO3, we will need 0.6022 mol of water. Now to calculate what mass that is:

mass(water)=number of moles*molar mass=0.6022mol*18.02g/mol=10.85g

5 0

3 years ago

What two things do all matter have in common?

ELEN [110]

Answer:

mass and occupies space

Explanation:

matter is made up of mass and mass takes up space

3 0

3 years ago

Read 2 more answers

How many grams of o2(g) are needed to completely burn 70.2 g of C3H8(g)

Lubov Fominskaja [6]

First you must write a balanced chemical equation.

C3H8 + 5O2 --> 3CO2 + 4H2O

From there, we can set up the stoichiometry equation to solve.

g O2= 70.2 g C3H8 X (1 mol C3H8/44.0962g C3H8) X (5 mol O2/1 mol C3H8) X (31.998g O2/1 mol O2)

Now solve, and you should get 254.7 g O2. Hope this helped!

6 0

3 years ago

Calculate the mass of ammonia (NH3) that contains a billion (1.00 * 10^12) hydrogen atoms.

Lynna [10]

Answer:

The mass of ammonia (NH3) that contains $1.00 \times 10^12$ hydrogen atoms is $9.4\times 10^{-12}$ g.

Explanation:

As $6.022\times 10^{23}$ atoms of hydrogen = 1 mole of the hydrogen atom

Therefore, $10^{12}$ atoms of hydrogen $= \frac{1}{6.022 \times 10^{23}}\times 10^{12}=1.66\times 10^{-12}$ moles of the hydrogen atom.

Now, there are 3 moles of hydrogen atoms in 1 mole of ammonia $(NH_3)$ .

As the mass of 1 mole of ammonia is 17g, so

when there are 3 moles of hydrogen atoms, then the mass of ammonia = 17 g

Therefore, when there are $1.66\times 10^{-12}$ moles of hydrogen atoms, then the mass of ammonia $= \frac{17}{3}\times 1.66\times 10^{-12}=9.4\times 10^{-12$ g.

Hence, the mass of ammonia $(NH_3)$ that contains $1.00 \times 10^12$ hydrogen atoms is $9.4\times 10^{-12}$ g.

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3 years ago

A heat lamp produces____<br> light.

Ipatiy [6.2K]

Answer:

infrared light

Explanation:

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3 years ago