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torisob [31]
3 years ago
8

If an element has 43 electrons, 56 neutrons, and 43 protons, what is its approximate atomic mass?

Chemistry
1 answer:
Bas_tet [7]3 years ago
4 0
Approximately 99 because there is the same amount of electrons and the only things that go into the nucleus is protons and neutrons.
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Energy in a chemical reaction can be identified as which of the following?
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I believe it’s A..but I’m not quite sure.
6 0
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Which property does a metal with a large number of free-flowing electrons most likely have?
Akimi4 [234]

a metal with a large number of free-flowing electrons most likely have good conductivity

6 0
3 years ago
Read 2 more answers
The activation energy of an uncatalyzed reaction is 70 kJ/mol. When a catalyst is added, the activation energy (at 20 °C) is 42
denis23 [38]

Answer:

T = 215.33 °C

Explanation:

The activation energy is given by the Arrhenius equation:

k = Ae^{\frac{-Ea}{RT}}

<u>Where:</u>

k: is the rate constant

A: is the frequency factor    

Ea: is the activation energy

R: is the gas constant = 8.314 J/(K*mol)

T: is the temperature

We have for the uncatalyzed reaction:

Ea₁ = 70 kJ/mol

And for the catalyzed reaction:

Ea₂ = 42 kJ/mol

T₂ = 20 °C = 293 K

The frequency factor A is constant and the initial concentrations are the same.

Since the rate of the uncatalyzed reaction (k₁) is equal to the rate of the catalyzed reaction (k₂), we have:

k_{1} = k_{2}

Ae^{\frac{-Ea_{1}}{RT_{1}}} = Ae^{\frac{-Ea_{2}}{RT_{2}}}   (1)

By solving equation (1) for T₁ we have:

T_{1} = \frac{T_{2}*Ea_{1}}{Ea_{2}} = \frac{293 K*70 kJ/mol}{42 kJ/mol} = 488. 33 K = 215.33 ^\circ C  

Therefore, we need to heat the solution at 215.33 °C so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction.

I hope it helps you!      

4 0
3 years ago
As you have seen, ozone is formed in the upper atmosphere through the reaction:
baherus [9]

The rate law equation for Ozone reaction

r=k[O][O₂]

<h3>Further explanation</h3>

Given

Reaction of Ozone :.

O(g) + O2(g) → O3(g)

Required

the rate law equation

Solution

The rate law is a chemical equation that shows the relationship between reaction rate and the concentration / pressure of the reactants

For reaction

aA + bB ⇒ C + D

The rate law can be formulated:

\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}

where

r = reaction rate, M / s

k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹

a = reaction order to A

b = reaction order to B

[A] = [B] = concentration of substances

So for Ozone reaction, the rate law (first orde for both O and O₂) :

\tt \boxed{\bold{r=k[O][O_2]}}

5 0
3 years ago
A 40.0 g drinking glass is filled with hot liquid. The liquid transfers 1,000. J of energy to the glass. If the temperature of t
lbvjy [14]
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