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3 years ago

Wine is 13 % alcohol by volume. How many milliliters of alcohol are in a 0.900-L bottle of wine?

Chemistry

2 answers:

seropon [69]3 years ago

8 0

Answer: The volume of alcohol present in 0.9 L of wine is 117 mL

Explanation:

We are given:

13 % alcohol by volume in wine.

This means that 13 mL of alcohol is present in 100 mL of wine.

We need to calculate the volume of alcohol in 0.9 L of wine.

Volume of wine = 0.9 L = 900 mL (Conversion factor: 1 L = 1000 mL)

By applying unitary method, we get:

In 100 mL of wine, volume of alcohol present is 13 mL

So, in 900 mL of wine, volume of alcohol present will be = $\frac{13}{100}\times 900=117mL$

Hence, the volume of alcohol present in 0.9 L of wine is 117 mL

AURORKA [14]3 years ago

3 0

13% of 0.900 is 0.117
there are 0.117 milliliters of alcohol in a 0.900-L bottle of wine.

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Hello,

The following information is missing, but I found it: "1.92 g of sodium sulfate is produced from the reaction of 4.9 g of sulfuric acid and 7.8 g of sodium hydroxide" so the undergoing chemical reaction is:

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