Question

A fish is 17.9 cm from the front surface of a fish bowl of radius 45 cm. Where does the fish appear to be to someone in air viewing it from in front of the bowl? Do not forget the proper sign.

Answer 1

Answer:

Fish will appear at distance 14.9 cm from the surface of bowl

Explanation:

As we know that fish is floating inside the water in fish bowl while it is observed from outside in air

so we have

$\frac{\mu_2}{d_i} - \frac{\mu_1}{d_o} = \frac{\mu_2 - \mu_1}{R}$

here we have

$\mu_2 = 1$

$\mu_1 = 1.33$

$d_o = 17.9 cm$

$R = 45 cm$

now we have

$\frac{1}{d_i} - \frac{1.33}{17.9} = \frac{1 - 1.33}{45}$

$d_i = 14.9 cm$