Answer: The E for Silver-silver Chloride electrode = 0.287 V
Explanation:
Silver/Silver Chloride (Ag/AgCl) with a value for E° that is actually +0.222 V or approximately 0.23 V has the actual potential of the half-cell prepared in this way as +0.197 V vs SHE, (Standard Hydrogen Electrode) which arises because in addition to KCl, there is the contribuion of AgCl to the chloride activity, which isn't exactly unity.
Therefore, the E for the Ag/AgCl electrode would approximately equal 0.287 V
Answer:
Density, 
Explanation:
Mass of a marble slab is 38.6 kg 38600 grams
The dimensions of the marble is 17 cm×23 cm×4 cm
We need to find its density. Mass per unit volume equals density. So,
So, the density of the marble slab is 
At a particular temperature, the solubility of He in water is 0.060 M when the partial pressure is 0.90 atm. 2.27 atm is the partial pressure of Kr would give a solubility of 0.150 M.
<h3>
What is Henry's Law ?</h3>
- According to Henry's law, the weight of a gas dissolved by a liquid is proportional to the pressure of the gas onto the liquid.
- With very few exceptions, a solute molecule in an extremely diluted solution will only have solvent molecules as its close neighbors. This means that the likelihood that a specific solute molecule will escape into the gas phase is predicted to be independent of the total concentration of solute molecules.
Solution:
The solubility of gas is directly proportional to partial pressure. It is expressed as:
S = 
where, S = Solubility of gas
= Henry's Law constant
= Partial pressure of gas
Now, put the values in above expression we get
0.060M = × 0.9 atm
= = 0.066 M/atm
Now we have to find the partial pressure of He
0.150 M = 0.066 M/atm ×
= 2.27 atm
Learn more about the Henry's Law : brainly.com/question/23204201
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<span>a. Use PV = nRT and solve for n = number of mols O2.
mols NO = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols O2 to mols NO2. Do the same for mols NO to mols NO2. It is likely that the two values will not be the same which means one is wrong; the correct value in LR (limiting reagent) problems is ALWAYS the smaller value and the reagent producing that value is the LR.
b.
Using the smaller value for mols NO2 from part a, substitute for n in PV = nRT, use the conditions listed in part b, and solve for V in liters. This will give you the theoretical yield (YY)in liters. The actual yield at these same conditions (AY) is 84.8 L.
</span>and % will be 60%.
Answer:
Mass = 74.9 g
Explanation:
Given data:
Number of atoms of arsenic = 6.02×10²³ atoms
Mass of arsenic = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022× 10²³ is called Avogadro number.
one mole = 6.02×10²³ atoms
So number of moles of arsenic are 1 mol.
Mass of arsenic:
Mass = number of moles × molar mass
Mass = 1 mol × 74.9 g/mol
Mass = 74.9 g
