Answer:
Concentration of nitrate in the new solution = 0.007 M
Explanation:
Given:
Concentration nitrate solution = 0.070 m
Volume of aliquote of the nitrate solution is add = 10.0 ml
Total volume = 100 ml
Find:
Concentration of nitrate in the new solution
Computation:
Number of M. mole = 0.070 m x 10.0 ml
Number of M. mole = 0.7 m-moles
Concentration of nitrate in the new solution = 0.7 m-moles / 100 ml
Concentration of nitrate in the new solution = 0.007 M
Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons.
Answer:
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1)The limiting reactant will be aluminum acetate
2) The mass of aluminum hydroxide formed will be 9.75 grams.
<h3>Stoichiometric problem</h3>
The equation of the reaction is as below:

The mole ratio of the 2 reactants is 1:3.
Mole of 100 mL. 1.25 mol/L
= 0.1 x 1.25 = 0.125 mol
Mole of 300 mL, 2.30 mol/L NaOH = 0.3 x 2.3 = 0.69 mol
Thus, aluminum acetate is limited.
Mole ratio of
and
= 1:1
Equivalent mole of
= 0.125 mol
Mass of 0.125 mole
= 0.125 x 78 = 9.75 grams.
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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