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3 years ago

Algebra help please?

Mathematics

2 answers:

katrin [286]3 years ago

6 0

The answer to that is -1.89041096 - 4.95890411 i

gtnhenbr [62]3 years ago

5 0

I/1+13i is simplified form

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Each table in the cafeteria can seat 10 students.how many tables are needed to seat 40 students

Vitek1552 [10]

Hi there!

To solve this problem, we need to divide the total amount of tables by the amount of students:

40 / 10 = 4

So, we need 4 tables to seat 40 students.

Hope this helps!

3 0

3 years ago

Read 2 more answers

The sum of two numbers is 3. The difference between five times the first number and four times the second number is 6. Find the

stellarik [79]

Answer:

1 and 2

2+1=3

2×5=10

1×4=4

10-4=6

4 0

3 years ago

NEED HELP DUE TODAYY!!!

svetoff [14.1K]

Answer:

144

Step-by-step explanation:

5x + 4x = 7x + 32

9x = 7x + 32

2x = 32

x = 16

7(16) + 32 = 144

I think this is correct

pls mark brainliest if good

7 0

3 years ago

For the line 2x+ 3y=6, the x-intercept is ____ and the y-intercept is ____.

Reptile [31]

Answer:

2 and 3

Step-by-step explanation:

the x-intercept is 2

the y-intercept is 3

8 0

3 years ago

Solve. Good luck! Please do not try to google this.

Elena L [17]

$\frac{x^{2} + x - 2}{6x^{2} - 3x} = \sqrt{2x} + \frac{3x^{2}}{2}$
$\frac{x^{2} + 2x - x - 2}{3x(x) - 3x(1)} = \frac{2\sqrt{2x}}{2} + \frac{3x^{2}}{2}$
$\frac{x(x) + x(2) - 1(x) - 1(2)}{3x(x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{x(x + 2) - 1(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$3x(2x - 1)(2\sqrt{2x} + 3x^{2}) = 2(x + 2)(x - 1)$
$3x(2x(2\sqrt{2x} + 3x^{2}) - 1(2\sqrt{2x} + 3x^{2}) = 2(x(x - 1) + 2(x - 1))$
$3x(2x(2\sqrt{2x}) + 2x(3x^{2}) - 1(2\sqrt{2x}) - 1(3x^{2})) = 2(x(x) - x(1) + 2(x) - 2(1)$
$3x(4x\sqrt{2x} + 6x^{3} - 2\sqrt{2x} - 3x^{2}) = 2(x^{2} - x + 2x - 2)$
$3x(4x\sqrt{2x} - 2\sqrt{2x} + 6x^{3} - 3x^{2}) = 2(x^{2} + x - 2)$
$3x(4x\sqrt{2x}) - 3x(2\sqrt{2x}) + 3x(6x^{3}) - 3x(3x^{2}) = 2(x^{2}) + 2(x) - 2(2)$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} + 18x^{4} - 9x^{3} = 2x^{2} + 2x - 4$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} = -18x^{4} + 9x^{3} + 2x^{2} + 2x - 4$
$6x\sqrt{2x}(2x) - 6x\sqrt{2x}(1) = -9x^{3}(2x) - 9x^{3}(-1) + 2(x^{2}) + 2(x) - 2(2)$
$6x\sqrt{2x}(2x - 1) = -9x^{3}(2x - 1) + 2(x^{2} + x - 2)$

5 0

3 years ago