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3 years ago

15

If the out come of a 1.0-kg ball moving at 3.0 m/s is 4.5 kinetic energy what would the kinetic energy be if the mass and speed

doubled

1 answer:

Flauer [41]3 years ago

7 0

Answer: KE = 36 J

Explanation: Solution:

KE = 1/2 mv²

= 1/2 ( 2 kg)(6 m/s)²

= 36 J

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How much force is required to accelerate a .6 kg object at 5 m/s^2

vodomira [7]

Answer:

$.$

» 30 N

Explanation:

<u>Given</u> :

Mass → m → 6kg

Acceleration → a →

$5 {ms}^{ - 2}$

<u>To</u><u> </u><u>find</u> :

The formula for force

F = m • a

F = 6 • 5

F = 30 N

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3 years ago

a ray of light incident on a mirror, at an angle of 45°. Another mirror is placed at an angle of 45° to the first ones as shown.

Gwar [14]

Answer:

If the ray of light is deflected by 45 degrees by the first mirror its total deflection by mirror (I) is 90 deg. (incident = 45 and exit ray equals 45 deg)

The second mirror will cause a net deflection of 90 degrees and the total deflection will be 180 deg or in opposite direction to the incident ray.

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2 years ago

Atoms of two different elements must have different

Tresset [83]

Answer:

Number of neautrons

Explanation:

Atoms from two different elements may have the same number of neutrons, but never the same number of protons. The number of protons is unique to the element and represents the atomic number. (sorcastic.org)

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3 years ago

A yellow ball with a mass of 2 kg is rolling across the floor at 3 m's A red ball with a mass of 3 kg is rolling across the

Wewaii [24]

Answer:
The red ball has a greater kinetic energy, because it has a greater mass

Explanation:
Mass is directly proportional to kinetic energy, as one increases, so does the other

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3 years ago

Read 2 more answers

A 3 mm inside diameter tube is placed in a fluid with a surface tension of 600 mN/m and density of 3.7 g/cm3. The contact angle

Aleks04 [339]

Answer: The height of the fluid rise is 0.01m

Explanation:

Using the equation

h = (2TcosѲ )/rpg

h= height of the fluid rise

diameter of the tube =3mm

radius of the tube= 3/2 =1.5mm=0.0015

T= surface tension = 600mN/m=0.6N/m

Ѳ = contact angle = $60^o$ C

p= density =3.7g/cm3= 3700kg/m3

g= acceleration due to gravity =9.8m/s2

h = ( 2*0.6*0.5)/(0.0015*3700*9.8)

h = 0.6/54.39

h= 0.01m

Therefore,the height of the fluid rise is 0.01m

8 0

3 years ago