For the reaction PCl5(g) + heat PCl3(g) + Cl2(g), what will happen when the volume is increased?

1 answer:

4 0

This is an aplication of Le Chatelier Principle. So, if you need further details about the theory behind the answer, search for this subject.

Here is the answer and the explanation.

You can realize that 1 mol of reactant produce 2 moles of products, which means that the trend of the reaction is to increase the volume (at constant pressure) or to increase the pressure (at constant volume). If you realease the pressure by increasing the volume, Le Chaelier principle permit you to predict a displacement of the equilibrium to the right (to the products). This is, because the equilibrium will try to restore (increase) the pressure by producing more molecules.

So, the answer is the option B. There will be a shift toward the products.

You might be interested in

What is the change in temperature in a 128g sample of titanium if it absorbs 2808J of heat energy at a temperature of 2°C? The s

Katena32 [7]

Given:

128g sample of titanium

2808J of heat energy

specific heat of titanium is 0.523 J/ g °C.

Required:

Change in temperature

Solution:

This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.

Plugging in the values into the equation

H = mCpT

2808J = (128g) (0.523 J /g °C) T

T = 41.9 °C

3 0

3 years ago

If 3.0 atm of pure HN3(g) is decomposed initially, what is the final total pressure in the reaction container? What are the part

lawyer [7]

This is an incomplete question, here is a complete question.

Hydrogen azide, HN₃, decomposes on heating by thefollowing unbalanced reaction:

$HN_3(g)\rightarrow N_2(g)+H_2(g)$

If 3.0 atm of pure HN₃ (g) is decomposed initially,what is the final total pressure in the reaction container? Whatare the partial pressures of nitrogen and hydrogen gas? Assume thatthe volume and temperature of the reaction container are constant.

Answer : The partial pressure of $N_2$ and $H_2$ gases are, 4.5 atm and 1.5 atm respectively.

Explanation :

The given unbalanced chemical reaction is:

$HN_3(g)\rightarrow N_2(g)+H_2(g)$

This reaction is an unbalanced chemical reaction because in this reaction number of hydrogen and nitrogen atoms are not balanced on both side of the reaction.

In order to balance the chemical equation, the coefficient '2' put before the $HN_3$ and the coefficient '3' put before the $N_2$ then we get the balanced chemical equation.