Answer:
Q >> Kc
We have more products than reactans. To reach the equilibrium, the balance will shift to the left.
Explanation:
Step 1: Data given
Temperature = 450.0 K
Kc = 4.62
When Kc > Q, we have more reactants than products. To reach the equilibrium, the balance will shift to the right
When Kc < Q, we have more products than reactans. To reach the equilibrium, the balance will shift to the left.
When Kc = Q,the equiation isatequilibrium
[SO3] = 0.254 M
[O2] = 0.00855 M
[SO2] = 0.500 M
Step 2: The balanced equation
2SO2(g) + O2(g) ⇄ 2SO3(g)
Step 3: Calculate the Q
Q = [SO3]² / [O2][SO2]²
Q = 0.254²/ (0.500 * 0.00855²)
Q = 1765
Q >> Kc
We have more products than reactans. To reach the equilibrium, the balance will shift to the left.
Explanation:
nephron is a functional unit of kidney
Food contamination is classified into three types: 1) Physical 2) Chemical Biological.
Physical contamination occurs if a paint chip falls into soup
It must be noted that, physical<span> contamination get into food through</span><span> poor procedural practices such as</span><span> dirt, hair, nail polish flakes, broken glass, nails, staples, plastic fragments, bones, bits of packaging, etc.</span>
Answer:
false should be the correct response.
Answer:
1.20 V
Explanation:
The standard cell potential is calculated from the expression
ε⁰ cell = ε⁰ oxidation + ε⁰ reduction
The species that will be reduced is the one with the higher standard reduction potential and the species that will be oxidized will be the one with the more negative reduction potential.
Thus for our question we will have
oxidation:
Pb(s) → Pb2+(aq) + 2 e- ε⁰ oxidation = - ε⁰ reduction
= - ( - 0.13 V ) = + 0.13 V
reduction
Br2(l) + 2 e- → 2 Br-(aq) ε⁰ reduction = +1.07 V
ε⁰ cell = ε⁰ oxidation + ε⁰ reduction = + 0.13 V + 1.07 V = 1.20 V
