Answer:
1375J
Explanation:
The gravitational potential/potential energy of the at the top of the tree which is the energy by virtue of its position.
P.E = mgh
mass = m
Acceleration due to gravity = g
height = h
At the top of the tree, the value of h (height) is high resulting in the gravitational potential. When the cat lands on the ground, the value of h is zero, the the gravitational potential would be zero and all the potential energy have been converted to other forms of energy.
Therefore, the total gravitational potential store is equal to the maximum amount of energy that can be transferred which is equal to 1375J.
The energy carried by a photon is equal to
(Planck's Konstant) times (the frequency of the photon) .
Planck's konstant is 6.626 x 10⁻³⁴ m²-kg/s (rounded)
Density: 1.9 g/cm3
density = mass/volume
d = 5.7/3
d = 1.9
