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FrozenT [24]
3 years ago
7

A mom pushes her 19.3 kg daughter on the swing. If she gives her an initial velocity of 7.5 m/s at the bottom of the swing and t

he swing sits 0.6 m above the ground at it's lowest point, what height does she reach above the ground?
Physics
1 answer:
kiruha [24]3 years ago
3 0

Answer:

3.17333333333? I hope I get it right

Explanation:

..................hello

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A tiger started running when it saw a deer running at uniform velocity 2m/s at 15m far from it ..if the tiger ran at acceleratio
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You need to set their position functions equal to one another and so for the time t when that is true. That is when the tiger and the deer are in the same place meaning the tiger catches the dear
Xdear= 2t+15 deer position function.
(I integrated the velocity function )
To get the Tigers position function you must integrate the acceleration twice. This becomes
Xtiger=t^2
Now t^2=2t+15
Time t is when the tiger catches the deer
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Explanation:

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