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Alona [7]
3 years ago
15

The right eye and right lung are __________.

Physics
1 answer:
PilotLPTM [1.2K]3 years ago
3 0

The correct answer is A) Ipsilateral

Explanation:

The term ipsilateral is commonly used to describe objects or structures that are on the same side of a body or structure. This term is correct to describe the right eye and the right lung because these two organs are on the same side of the body (the right side). This can also be used to describe other organs such as the left humerus and the left hand or the right ear and the right feet because these pairs are also on the same side. According to this, the correct answer is A.

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The only force acting on a 2.9 kg canister that is moving in an xy plane has a magnitude of 7.5 N. The canister initially has a
Elodia [21]

Answer:15.66 J

Explanation:

mass of block \left ( m\right )=2.9 kg

Force magnitude=7.5 N

Initial velocity =3.9\hat{i} m/s

Final velocity=5.1 \hat{j} m/s

Initial Kinetic Energy=\frac{1}{2}mv^2

=\frac{1}{2}\times 2.9\times 3.9^2=22.05 J

Final Kinetic Energy=\frac{1}{2}mv^2

=\frac{1}{2}\times 2.9\times 5.1^2=37.714 J

Work Done =Final -Initial Kinetic energy=37.714-22.056=15.66 J

7 0
4 years ago
At room temperature, an oxygen molecule, with mass of 5.31x10^-26kg , typically has a kinetic energy of about 6.21x10^-21J. How
den301095 [7]

Answer:

V=483.63 m/s

Explanation:

Given that

mass ,m= 5.31 x 10⁻²⁶ kg

Kinetic energy KE= 6.21 x 10⁻²¹ J

As we know that the kinetic energy of the mass m with moving velocity V given as

KE=\dfrac{1}{2}mV^2  

Now by putting the values

6.21\times 10^{-21}=\dfrac{1}{2}\times 5.31\times 10^{-26}\times V^2

V^2=\dfrac{2\times 6.21\times 10^{-21}}{5.31\times 10^{-26}}

V^2=233898.30

V=\sqrt{233898.30}\ m/s

V=483.63 m/s

Therefore the velocity of the molecule at the room temperature will be 483.63 m/s.

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