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aliya0001 [1]
3 years ago
9

How is oxagen made into an atom

Physics
1 answer:
Butoxors [25]3 years ago
8 0
An oxygen atom is heavier than a hydrogen or a helium atom, and even heavier than a carbon atom. That's because an oxygen atom has eight protons and eight neutrons, and eight electrons going around the outside. ... Some oxygen atoms combine with carbon atoms to make carbon dioxide, which plants breathe.
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Can someone help me please it is number 7
motikmotik
D. The string vibrated because of resonance, which happened because the tuning fork and guitar string have same natural frequency.
4 0
4 years ago
A wheel with radius 36 cm is rotating at a rate of 19 rev/s.(a) What is the angular speed in radians per second? rad/s(b) In a t
Sedaia [141]

(a) 119.3 rad/s

The angular speed of the wheel is

\omega= 19 rev/s

we need to convert it into radiands per second. We know that

1 rev = 2 \pi rad

Therefore, we just need to multiply the angular speed of the wheel by this factor, to get the angular speed in rad/s:

\omega = 19 rev/s \cdot (2\pi rad/rev))=119.3 rad/s

(b) 596.5 rad

The angular displacement of the wheel in a time interval t is given by

\theta= \omega t

where

\omega=119.3 rad

and

t = 5 s is the time interval

Substituting numbers into the equation, we find

\theta=(119.3 rad/s)(5 s)=596.5 rad

(c) 127.3 rad/s

At t=10 s, the angular speed begins to increase with an angular acceleration of

\alpha = 1.6 rad/s^2

So the final angular speed will be given by

\omega_f = \omega_i + \alpha \Delta t

where

\omega_i = 119.3 rad/s is the initial angular speed

\alpha = 1.6 rad/s^2 is the angular acceleration

\Delta t = 15 s - 10 s = 5 s is the time interval

Solving the equation,

\omega_f = (119.3 rad/s) + (1.6 rad/s^2)(5 s)=127.3 rad/s

(d) 616.5 rad

The angle through which the wheel has rotated during this time interval is given by

\theta = \omega_i \Delta t + \frac{1}{2} \alpha (\Delta t)^2

Substituting the numbers into the equation, we find

\theta = (119.3 rad/s)(5 s) + \frac{1}{2} (1.6 rad/s^2) (5 s)^2=616.5 rad

(e) 222 m

The instantaneous speed of the center of the wheel is given by

v_{CM} = \omega R (1)

where

\omega is the average angular velocity of the wheel during the time t=10 s and t=15 s, and it is given by

\omega=\frac{\omega_i + \omega_f}{2}=\frac{127.3 rad/s+119.3 rad/s}{2}=123.3 rad/s

and

R = 36 cm = 0.36 m is the radius of the wheel

Substituting into (1),

v_{CM}=(123.3 rad/s)(0.36 m)=44.4 m/s

And so the displacement of the center of the wheel will be

d=v_{CM} t = (44.4 m/s)(5 s)=222 m

8 0
3 years ago
Neon, helium, methane, krypton, xenon, hydrogen, and ozone make up & what of the atmosphere
Alinara [238K]
Part of the upper atmosphere

6 0
3 years ago
In which type of wave do air particles move together or apart parallel to the direction of the wave?
Phoenix [80]
The best and most correct answer among the choices provided by the question is <span>B.sound waves</span><span>.
</span>

<span>Particles move together or apart parallel to the direction of the sound wave.
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Hope my answer would be a great help for you.    
If you have more questions feel free to ask here at Brainly.
8 0
4 years ago
Please help!!!
Dominik [7]

Answer:

i Believe the correct answer is "An open circuit being changed into a closed circuit"

Explanation:

8 0
3 years ago
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