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aliya0001 [1]
3 years ago
9

How is oxagen made into an atom

Physics
1 answer:
Butoxors [25]3 years ago
8 0
An oxygen atom is heavier than a hydrogen or a helium atom, and even heavier than a carbon atom. That's because an oxygen atom has eight protons and eight neutrons, and eight electrons going around the outside. ... Some oxygen atoms combine with carbon atoms to make carbon dioxide, which plants breathe.
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A satellite with mass 500 kg is placed in a circular orbit about Earth (Mass= 5.98 x 10^24 kg), radius = (6.4 x 10^6), a distanc
gizmo_the_mogwai [7]

Explanation:

a) F = GmM / r²

F = (6.67×10⁻¹¹) (500) (5.98×10²⁴) / (6.4×10⁶ + 1.5×10⁶)²

F = 3200 N

b) F = ma

3200 = 500a

a = 6.4 m/s²

c) a = v² / r

640 = v² / (6.4×10⁶ + 1.5×10⁶)

v = 7100 m/s

4 0
3 years ago
When a positively charged body touches a neutral body, the neutral body will
PtichkaEL [24]
Become more positive instead of negative
7 0
3 years ago
What is one difference between water and ice?
Gemiola [76]
<span>Well, ice is NOT more compressed than water.
Ice molecules do NOT have more charge than water molecules.
Water does NOT have a lower temperature than ice.
But water molecules DO move around more easily than ice molecules</span>
5 0
3 years ago
Read 2 more answers
Which statement is NOT true about "p" orbitals? Which statement is NOT true about "p" orbitals? A 3p orbital has a higher energy
ki77a [65]

Answer:

Option E is correction. None of the above.

Explanation:

    ( 1 ) A 3p orbital has more energy than 2p orbital and this is the reason it is away from the nucleus as compare to 2p orbital. Energy of the shells increases as their distance increases from the nucleus.

    (2) p subshells are made up of three dumbbell-shaped orbitals

    (3) There are three atomic orbitals in a p subshell. They are px, py, and pz.

3 0
4 years ago
Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge th
statuscvo [17]

Answer:

 P /K = 1,997 10⁻³⁶  s⁻¹

Explanation:

For this exercise let's start by finding the radiation emitted from the accelerator

       \frac{dE}{dt} = \frac{q^{2} a^{2} }{6\pi  \epsilon_{o} c^{2}    }

the radius of the orbit is the radius of the accelerator a = r = 0.530 m

let's calculate

       \frac{dE}{dt} = [(1.6 10⁻¹⁹)² 0.530²] / [6π 8.85 10⁻¹² (3 108)³]

      P= \frac{dE}{dt}= 1.597 10⁻⁵⁴ W

Now let's reduce the kinetic energy to SI units

       K = 5.0 10⁶ eV (1.6 10⁻¹⁹ J / 1 eV) = 8.0 10⁻¹⁹ J

the fraction of energy emitted is

      P / K = 1.597 10⁻⁵⁴ / 8.0 10⁻¹⁹

      P /K = 1,997 10⁻³⁶  s⁻¹

3 0
3 years ago
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