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4 years ago

PLEASE HELP I WILL GIVE MAX POINTS

Physics

2 answers:

KatRina [158]4 years ago

8 0

Collect the water sample in a glass tumbler and then put a straw in the water. Record the bending in the straw using a protractor and the angle is the answer required

Finger [1]4 years ago

4 0

you can collect water and shine a light though it and record your finings

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Which of the following statements about Boyle's law are correct? The temperature and pressure must remain constant for the law t

kvasek [131]

Answer: The temperature and the number of molecules must reamain constant for the law to apply, and as the pressure increases, the volumen decreases proportionally.

Boyle's law states that if the temperature, T, of a given mass of gas, remains constant, the Volume, V, of the gas is in inverse relation to the pressure, p; i.e.

pV = constant (for a given mass of gas, at constant T)

Then, if p increases, V decreases proportionally to keep the relation pV = constant.

8 0

3 years ago

Read 2 more answers

A 14.0 g wad of sticky clay is hurled horizontally at a 110 g wooden block initially at rest on a horizontal surface. The clay s

ahrayia [7]

Answer:

86.53 m/s

Explanation:

Given:

Mass of clay (m) = 14.0 g = 0.014 kg

Mass of block (M) = 110 g = 0.110 kg

Initial speed of block (U) = 0 m/s

Sliding distance (d) = 7.50 m

Coefficient of friction between block and surface (μ) = 0.650

Let the initial speed of clay be 'u' and speed of clay and block just after collision be 'v'.

Now, momentum is conserved just before and just after collision.

Momentum just before collision = $mu + 0 = mu$

Momentum just after collision = $(m + M)v$

Therefore, $mu=(M+m)v$ --------- (1)

Now, using newton's second law and we find the acceleration of the system.

The frictional force is given as:

$f=\mu mg=-ma\\\\a=-\mu g$

Now, using equation of motion, we can find the velocity just after collision.

$0^2=v^2+2ad\\\\v=\sqrt{-2ad}\\\\v=\sqrt{-2\times (-\mu g)\times d}\\\\v=\sqrt{2\mu gd}$

Plug in the given values and find 'v'. This gives,

$v=\sqrt{2\times 0.650\times 9.8\times 7.50}\\\\v=\sqrt{95.55}=9.77\ m/s$

Now, using equation (1) and substituting the given values, we get:

$0.014u=(0.014+0.110)\times 9.77\\\\u=\frac{0.124\times 9.77}{0.014}\\\\u=86.53\ m/s$

Therefore, the speed of the clay immediately before impact is 86.53 m/s.

7 0

3 years ago

A truck exerts 2700 N of force on a car that is stuck in the mud, and does not move. How much work has the truck performed?

vova2212 [387]

Answer:

zero

Explanation:

although force was applied as long as there's no movement ,no work has been done

mathematically;work=force×distance

work=2700×0

work=0J

hope I helped

please like and Mark as brainliest

5 0

4 years ago

A uniform rod 8m long weighing 5kg is supported horizontally by two vertical parallel strings at p and q and at distance 2m and

Gala2k [10]

Answer:

Fp = 36 N

Fq = 58 N

Explanation:

Let the left end be the reference end with string p closest to it.

Let CCW moments be positive

Sum moments about p to zero

1(9.8)[2 - 1] + Fq[6 - 2] - 5(9.8)[8/2 - 2] - 1.5(9.8)[5 - 2] - 2(9.8)[7 - 2] = 0

Fq[4] = 23.5(9.8)

Fq = 57.575 ≈ 58 N

Sum moments about q to zero

1(9.8)[6 - 1] - Fp[6 - 2] + 5(9.8)[6 - 8/2] + 1.5(9.8)[6 - 5] - 2(9.8)[7 - 6] = 0

Fp = 35.525 N

Sum vertical forces to zero

Fp + 57.575 - (9.8)(1 + 1.5 + 2 + 5) = 0

Fp = 35.525 ≈ 36 N

4 0

2 years ago

Scientific laws and theories did not begin as questions and hypothesis? True or false

Nesterboy [21]

False. That's exactly how scientific theories begin

8 0

3 years ago