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4 years ago

HELP FAST If a ball is thrown with a force of .5N and an acceleration of 2.0m/s^2, what is the balls mass?

Physics

2 answers:

user100 [1]4 years ago

8 0

Answer:

0.25 kg

Explanation:

Newton's second law states that:

$F=ma$

where

F is the net force acting on an object

m is the object's mass

a is its acceleration

In this problem, we have:

$F=0.5 N$ is the force exerted on the object

m is the ball's mass

$a=2.0 m/s^2$ is its acceleration

Solving the formula for m, we can find the ball's mass:

$m=\frac{F}{a}=\frac{0.5 N}{2.0 m/s^2}=0.25 kg$

tamaranim1 [39]4 years ago

7 0

Answer:

0.25kg (uwu)

Explanation:

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VikaD [51]

Answer:

According to the law of conservation of momentum:

Momentum of the car and insect system before collision = Momentum of the car and insect

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Hence, the change in momentum of the car and insect system is zero.

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3 years ago

Acar goes from 20m/s to 30m/s in 10 seconds what is its acceleration

prohojiy [21]

Acceleration = change in velocity/change in time

= (30 - 20) / 10 - 0

= 10 / 10

Acceleration = 1 m/s²

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3 years ago

A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.

kodGreya [7K]

Answer:

The z-component of the force is $\= F_z = 0.00141 \ N$

Explanation:

From the question we are told that

The charge on the particle is $q = 7.76 *0^{-8} \ C$

The magnitude of the magnetic field is $B = 0.700\r i \ T$

The velocity of the particle toward the x-direction is $v_x = -1.68*10^{4}\r i \ m/s$

The velocity of the particle toward the y-direction is

$v_y = -2.61*10^{4}\ \r j \ m/s$

The velocity of the particle toward the z-direction is

$v_y = -5.85*10^{4}\ \r k \ m/s$

Generally the force on this particle is mathematically represented as

$\= F = q (\= v X \= B )$

So we have

$\= F = q ( v_x \r i + v_y \r j + v_z \r k ) \ \ X \ ( \= B i)$

$\= F = q (v_y B(-\r k) + v_z B\r j)$

substituting values

$\= F = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r z) + [(5.58*10^{4}) (0.700)]\r y)$

$\= F= 0.00303\ \r j +0.00141\ \r k$

So the z-component of the force is $\= F_z = 0.00141 \ N$

Note : The cross-multiplication template of unit vectors is shown on the first uploaded image ( From Wikibooks ).

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4 years ago

Use the drop-down menus to order the steps for writing chemical names.

jekas [21]

Answer:3,2,4,5,1

Explanation:

I just did it on edgenuity

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3 years ago

Read 2 more answers

Two radio antennas A and B radiate in phase. Antenna B is a distance of 130 m to the right of antenna A. Consider point Q along

hoa [83]

Answer:

constructive λ = 130 m

destructive λ = 260 m

Explanation:

a) the expression for constructive interference is that the difference in amino is equal to a multiple of the average wavelength

AQ - BQ = 2m λ/ 2 m = 0, 1, 2, ...

Where

AQ = 130 +50 = 180 m

BQ = 50 m

To find the smallest wavelength let's use m = 1

180 - 50 = 2 1 λ/ 2

λ = 130 m

b) for destructive interference

AQ –BQ = (2m + 1) λ/2

The smallest value is for m = 0

130 = λ / 2

λ = 260 m

3 0

3 years ago