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ad-work [718]
2 years ago
12

If you cook a marshmallow a few feet above a camp fire, it will cook mostly

Physics
1 answer:
nasty-shy [4]2 years ago
6 0

Answer:

A) radiation.

Explanation:

Hello,

In this case, heat transfer from a body with a high temperature to a body with a lower temperature may occur when the bodies are not in direct physical contact with each other or when they are separated in space and it is is called heat radiation. Solids, liquids, or gaseous substances are able to emit energy via a process of electromagnetic radiation because of vibrational and rotational movement of their molecules and atoms.

Hence, since the camp fire is not in contact with the marshmallow and it still cooks it, we can infer that the mechanism of heat transfer is A) radiation. Moreover, both conduction and convection occur when the bodies are in contact.

Regards.

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You are driving down the highway late one night at 20 m/s when a deer steps onto the road 35m in front of you. Your reaction tim
8090 [49]

Answer:

- Distance between car and the deer when the car stopped = 20 m

- The time required for you to stop once you press the brakes = less than 5 s in order not to hit the deer.

Explanation:

Using the equations of motion,

In the 0.5 s reaction time, we need to first calculate how far he has travelled in that time.

a = 0 m/s² (Since the car is travelling at constant velocity)

x = ?

Initial velocity = u = 20 m/s

x = ut + at²/2

x = 20×0.5 + 0 = 10 m

From that moment,

a = - 10 m/s²

u = initial velocity at the start of the deceleration = 10 m/s

v = final velocity = 0 m/s

x = ?

v² = u² + 2ax

0² = 10² + 2(-10)(x)

20x = 100

x = 5 m

Total distance travelled from when the deer stepped onto the road = 10 + 5 = 15 m

Distance between car and the deer when the car stopped = 35 - 15 = 20 m

b) To determine the time required to stop once you step on the brakes

u = 10 m/s

t = ?

v = 0 m/s²

x = distance from when the brake was stepped on to the deer = 35 - 10 = 25 m

x = (u + v)t/2

25 = (10 + 0)t/2

10t = 50

t = 5 s

Meaning the time required to stop once you step on the brakes is less than 5s.

6 0
3 years ago
What force in Newton is required to accelerate a car starting from rest to 20 m/s in 15 seconds if the mass of the car is 2500 k
Lyrx [107]

We will solve this question using the second law of motion which states that force is directly equal to the product of mass and acceleration.

\sf \: F=ma

Where,

  • F is force
  • m is mass
  • a is acceleration

In our case,

  • F = ?
  • m = 2500 kg
  • a = 20m/s

\tt \: F_{net}  = 2500 \times 20 \\   \tt= 50000

<em>Thus, The force of 50000 Newton is required to accelerate a car of 2500 kg...~</em>

3 0
2 years ago
Read 2 more answers
Which of the following forms matter?<br> A. Proteins<br> B.atoms<br> C.cells<br> D. DNA
Artemon [7]

Answer:b) atoms

Explanation:which are in turn made up of protons, neutrons and electrons

8 0
2 years ago
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Which tuning forks will give rise to a beat frequency of 20 Hz when sounded together with a 240 Hz tuning fork?
Lubov Fominskaja [6]

Use the concept of beat frequency to find the applicable final freqeuncy for 20Hz beat frequency.

Beat can be defined as 'the interference pattern between two sounds of slightly different frequencies0

The expression for beat frequency is given as

f_{beat} = |f_1-f_2|

Where,

f_2 = Final frequency

f_1 = Initial frequency

The beat frequency for us is 25Hz and the initial frequency is 240Hz, then

20= |f_2-240|

Being an absolute value, two values are possible, both in addition and subtraction:

f_2 = 240 \pm 20

The two possible values are

f_2 = 220Hz

f_2 = 260Hz

3 0
2 years ago
Newton's first law states that objects do not change their velocity unless acted upon
Viefleur [7K]

Answer:

Air resistance/Drag (this is the proper term for air resistance) or gravity or friction

It depends on the direction and if you throw it across a surface or if you throw it straight upwards.

I hope this helps!!

8 0
2 years ago
Read 2 more answers
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