The answer is approximately 2.998e+8
Answer:
A) 4.035 × 10^(9) J
B) 9.29 × 10^(9) J
Explanation:
We are given;
Capacitance of the original capacitor; C = 1.33 F
Potential difference given to the original capacitor; V = 77.9 kV = 77.9 × 10³ V
A) The formula for Potential energy (U) for the original capacitor is given as:
U = ½CV²
Plugging in the relevant values, we have;
U = ½ × 1.33 × (77.9 × 10³)²
U = 4.035 × 10^(9) J
B) We are told that the capacitor with dielectric constant of 427, was replaced with one possessing a dielectric constant of 983.
Thus;
U = ½ × 1.33 × (983/427) × (77.9 × 10³)²
U = 9.29 × 10^(9) J
Answer:
W = 100000 J = 100 KJ
Explanation:
Here we will use the most basic and general formula of work, which is as follows:
where,
W = Work Done = ?
F = Force Required = 200 N
d = Length of Track = 500 m
Therefore,
<u>W = 100000 J = 100 KJ</u>
It wears down its components causing it to not work as effectively, it also creates heat which can cause(according on the machine) it to burn out. Another Immediate problem is that it can slow the machine causing it to lose efficiency.
Answer:
25.2563 m/s
Explanation
This is the equation needed
So Just plug in!