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Radda [10]
3 years ago
13

HZ is a weak acid. An aqueous solution of HZ is prepared by dissolving 0.020 mol of HZ in sufficient water to yield 1.0 L of sol

ution. The pH of the solution was 4.93 at 25.0°C. What is the Ka of HZ?
Chemistry
1 answer:
dlinn [17]3 years ago
7 0

Answer: below is the calculation for Ka

Explanation:

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30)
Feliz [49]

Answer:

D has to be based on facts so d would be the answer and idea that can only be proven true those are facts not hypothesis or guesses

Explanation:

based on a body of facts that have been repeatedly confirmed through observation and experiment. Such fact-supported theories are not "guesses" but reliable accounts of the real world."

6 0
2 years ago
How many oxygen atoms are present in the compound aluminum sulfate?
yawa3891 [41]
I believe that there are 12 oxygen atoms in aluminum sulfate, And 1 Sulfur and 2 aluminum. If you need anything else let me know.
5 0
3 years ago
39. Which bond is least polar?<br> A) As-C1<br> B) Bi-CI<br> C) P-CI<br> D) N-C1
garik1379 [7]

Answer:

D) N-Cl.

Explanation:

The electronegativity of the elements in Group 5 (N. P As and Bi) decreases as we go down the Group so N is the most electronegative and chlorine is less able to draw electrons away from N than from the other elements in Group 5.

3 0
3 years ago
A sucrose packet contains 4.0g sucrose C12H22O11, how many moles of sucrose does the packet contain?
SpyIntel [72]

Answer:

And we have to calculate the number of moles of sucrose present in a lb mass of sucrose: Moles of sucrose=454⋅g342.30⋅g⋅mol−1=1.33⋅mol .

Explanation:

<u>Brainliest</u><u> </u><u>Answer </u><u>Pls</u>

8 0
3 years ago
Calcular la presión final de un gas que inicialmente está a 21°C y 0,98 atm. Sabiendo que su temperatura aumenta a 37°C.
KatRina [158]

Answer:

1.03 atm

Explanation:

Primero <u>convertimos 21 °C y 37 °C a K</u>:

  • 21 °C + 273.16 = 294.16 K
  • 37 °C + 273.16 = 310.16 K

Una vez tenemos las temperaturas absolutas, podemos resolver este problema usando la<em> ley de Gay-Lussac</em>:

  • T₁P₂ = T₂P₁

En este caso:

  • T₁ = 294.16 K
  • P₂ = ?
  • T₂ = 310.16 K
  • P₁ = 0.98 atm

Colocando los datos:

  • 294.16 K * P₂ = 310.16 K * 0.98 atm

Y <u>despejando P₂</u>:

  • P₂ = 1.03 atm
7 0
2 years ago
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