Answer:
Explanation:
The balanced equation is
I₂(g) + Br₂(g) ⇌ 2IBr(g)
Data:
Kc = 8.50 × 10⁻³
n(IBr) = 0.0600 mol
V = 1.0 L
1. Calculate [IBr]
![\text{[IBr]} = \dfrac{\text{0.0600 mol}}{\text{1.0 L}} = \text{0.0600 mol/L}](https://tex.z-dn.net/?f=%5Ctext%7B%5BIBr%5D%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B0.0600%20mol%7D%7D%7B%5Ctext%7B1.0%20L%7D%7D%20%3D%20%5Ctext%7B0.0600%20mol%2FL%7D)
2. Set up an ICE table.
3. Calculate [I₂]
![\begin{array}{rcl}K_{\text{c}}&=&\dfrac{\text{[IBr]}^{2}} {\text{[I$_{2}$][Br]$_{2}$}}\\\\8.50 \times 10^{-2}&=&{\dfrac{(0.0600 - 2x)^{2}}{x^{2}}}& &\\\\0.2915x & = &{\dfrac{0.0600 - 2x}{x}}& &\\\\0.2915x & = &0.0600 - 2x\\\\2.2915x & = & 0.0600\\x & = & \textbf{0.026 18 mol/L}\\\end{array}\\](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7DK_%7B%5Ctext%7Bc%7D%7D%26%3D%26%5Cdfrac%7B%5Ctext%7B%5BIBr%5D%7D%5E%7B2%7D%7D%20%7B%5Ctext%7B%5BI%24_%7B2%7D%24%5D%5BBr%5D%24_%7B2%7D%24%7D%7D%5C%5C%5C%5C8.50%20%5Ctimes%2010%5E%7B-2%7D%26%3D%26%7B%5Cdfrac%7B%280.0600%20-%202x%29%5E%7B2%7D%7D%7Bx%5E%7B2%7D%7D%7D%26%20%26%5C%5C%5C%5C0.2915x%20%26%20%3D%20%26%7B%5Cdfrac%7B0.0600%20-%202x%7D%7Bx%7D%7D%26%20%26%5C%5C%5C%5C0.2915x%20%26%20%3D%20%260.0600%20-%202x%5C%5C%5C%5C2.2915x%20%26%20%3D%20%26%200.0600%5C%5Cx%20%26%20%3D%20%26%20%5Ctextbf%7B0.026%2018%20mol%2FL%7D%5C%5C%5Cend%7Barray%7D%5C%5C)
4. Convert the temperature to kelvins
T = (150 + 273.15) K = 423.15 K
5. Calculate p(I₂)
C3H8 and CH4 are two compounds made from the same two elements, C and H. The ratios of C and H for both are round numbers.
Law of multiple proportions states that when two elements combine with each other to form more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers.
So the ans is C) Law of Multiple Proportions
Answer:
25.2°C
Explanation:
Given parameters:
Energy applied to the water = 1000J
Mass of water = 50g
Final temperature = 30°C
Unknown:
Initial temperature = ?
Solution:
To solve this problem, we use the expression below:
H = m c Ф
H is the energy absorbed
m is the mass
c is the specific heat capacity
Ф is the change in temperature
1000 = 50 x 4.184 x (30 - initial temperature )
1000 = 209.2(30 - initial temperature)
4.78 = 30 - initial temperature
4.78 - 30 = - initial temperature
Initial temperature = 25.2°C
When water is boiled, the heat energy is transferred to the molecules of water, which begin to move more quickly. Eventually, the molecules have too much energy to stay connected as a liquid. When this occurs, they form gaseous molecules of water vapor, which float to the surface as bubbles and travel into the air.
