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tester [92]
3 years ago
5

(20 Points) If you use a 40x objective to magnify a slide, the image you see through the eyepiece will be magnified:

Chemistry
2 answers:
Alona [7]3 years ago
8 0
B. 40 times

Hope this helps<3
lisabon 2012 [21]3 years ago
7 0
B. 40 times
Please mark as brainliest.
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Describe how sediments are produced by weathering and erosion
TEA [102]
Weathering is the physical or chemical process where rocks are broken down to form sediments.
 • Physical weathering does not change the rock’s composition.
 • Chemical weathering does change the rock’s composition
 • Erosion is the process where forces such as water, wind, ice, or gravity transport sediments to some remote location
5 0
3 years ago
Read 2 more answers
PLEASE HELP!!
wariber [46]

Answer:

answer is option 2 hope it helps

8 0
3 years ago
Gaseous methane CH4 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. What is the t
Murrr4er [49]

Answer:

50.8 g

Explanation:

Equation of reaction.

CH_4 + 2O_2 \to CO_2 + 2H_2O

From the given information, the number of moles of methane = mass/ molar mass

= 15.4 g /  16.04 g/mol

= 0.960 mol

number of moles of oxygen gas = 90.3 g / 32 g/ mol

= 2.82 mol

Since 1 mol of methane requires 2 moles of oxygen

Then 0.960 mol of methane will require = 0.960 mol × 2 = 1.92 mol of oxygen gas

Thus, methane serves as a limiting reagent.

2.82 mol oxygen gas will result in 2.82 moles of water

So, the theoretical yield of water = moles × molar mass

= 2.82 mol × 18.01528 g/mol

= 50.8 g

8 0
3 years ago
The radioactive decay of a certain sample produced 846 disintegrations per minute. exactly 3.00 days later, the rate of decay wa
Margarita [4]

Answer:

\boxed{\text{1.81 da}}

Explanation:

1. Calculate the decay constant

The integrated rate law for radioactive decay is 1

\ln\dfrac{A_{0}}{A_{t}} = kt

where

A₀ and A_t are the counts at t = 0 and t

k is the radioactive decay constant

\ln \dfrac{846}{269} = k \times 3.00\\\\\ln3.145 = 3.00k\\1.146 = 3.00k\\\\k =\dfrac{1.146}{3}\\\\k = \text{0.382 /da}\\

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{0.382} = \text{1.81 da}

The half-life for decay is \boxed{\textbf{1.81 da}}.

3 0
3 years ago
Is trimming a bush because it grows too tall a chemical or physical change
professor190 [17]

Answer:

Physical Change

Explanation:

The bush is changing shapes, not changing what it is.

8 0
3 years ago
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