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3 years ago

(20 Points) If you use a 40x objective to magnify a slide, the image you see through the eyepiece will be magnified:

Chemistry

2 answers:

Alona [7]3 years ago

8 0

B. 40 times

Hope this helps<3

lisabon 2012 [21]3 years ago

7 0

B. 40 times
Please mark as brainliest.

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How much percent of shops are in the city? How about in the country?

kolezko [41]

Answer:

I would say there would be 5-10% in a city, and maybe 10-20% in the country. It mainly varies depending on how big the city is, how many people/districts there are, and the size of the country, which makes it hard to give a certain percent of shops, as there may be small businesses included as well or new shops being built.

Hope this helps! This was pretty confusing for me as well so i hope the answer is alright (×﹏×)

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1 year ago

How many grams Kl are needed to prepare 100.mL of 0.55M solution?

Makovka662 [10]

Answer:

Explanation:

100mL = 0.1L

0.55 M = mol/0.1 L

mol = 0.055 mol

molar mass of KI = 165.998 g

0.055 * 165.998 = 9.13 g of KI

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1 year ago

which of the following compounds would be considered an electrolyte? a. c6h12o6 b. naoh c. co2 d. agcl

AlekseyPX

Answer: B: NaOH

Explanation:

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6 months ago

Because of friction?

Zanzabum

Answer:

what do you mean?

Explanation:

5 0

2 years ago

Read 2 more answers

Write equations that show the processes that describe the first, second, and third ionization energies for a gaseous gadolinium

Inessa [10]

Answer:

Gd(g) → $Gd^{+}(g) + e^{-}$ , $Gd^{+}(g)$ → $Gd^{2+}(g) + e^{-}$ , $Gd^{2+}(g)$ → $Gd^{3+}(g) + e^{-}$

Explanation:

Ionization energy is the energy required to remove an electron from a gaseous atom or ion.

The first ionization energy is the energy required to remove the valence electron(outermost) from a neutral atom:

Gd(g)→ $Gd^{+}(g) + e^{-}$

The second ionization energy is the energy required to remove next/second electron from $x^{+}$ ion. The second ionization energy is always higher than the first:

$Gd^{+}$ (g) → $Gd^{2+}(g) + e^{-}$

The third ionization energy is the energy required to remove third electron from $x^{2+}$ ion:

$Gd^{2+}$ (g) → $Gd^{3+}(g) + e^{-}$

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2 years ago