Here is the full question:
Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)
1.000 g copper wire is reacted with 10 mL of concentrated nitric acid (16M). If 0.953 g of copper was actually recovered at the end of the entire experiment, what would be the percent yield?
Answer:
95.30 %
Explanation:
equation for the reaction is given as:
Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)
1.00 g of Cu = 
= 0.01574 mol of Cu
10 mL of 16 M HNO3 = 
= 0.16 mol of HNO3
However, from both variables; we can arrive at a conclusion that Cu is the limiting reagent.
therefore % yield = = 4.70 %
Percentage yield = 
Percentage yield = 
%
Percentage yield = 0.953 × 100%
Percentage yield = 95.30 %
AuI3, or Gold Iodide.
Hope this helps! :)
<u>Answer:</u> The given isotope of tin has 50 protons and 69 neutrons.
<u>Explanation:</u>
Atomic number is defined as the number of protons or number of electrons that are present in neutral atom. It is represented as Z.
Atomic number = Number of protons = Number of electrons
Mass number is defined as the sum of number of protons and number of neutrons. It is represented as A.
Mass number = Number of protons + Number of neutrons
We are given:
An isotope having representation 
Mass number of Sn = 19
Atomic number = 50
Number of neutrons = Mass number - Atomic number = 119 - 50 = 69
Hence, the given isotope of tin has 50 protons and 69 neutrons.
True that in the preindustrial era, settlements were more likely to be near sources of surface water than in the industrial era. The main reason being that during the preindustrial era people were dependent mostly on irrigation. For irrigation people were dependent on surface water. This was the main and basic reason.
