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juin [17]
3 years ago
13

Calculate the average atomic mass of argon to two decimal places, given the following relative atomic masses and abundances of e

ach of the isotopes: argon-36 (35.97 u; 0.337%), argon-38 (37.96 u; 0.063%), and argon-40 (39.96 u; 99.600%)
Chemistry
1 answer:
user100 [1]3 years ago
4 0

Answer:

39.95 u

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})+(\frac {\%\ of\ the\ third\ isotope}{100}\times {Mass\ of\ the\ third\ isotope})

Given that:

<u>For first isotope, Argon-36: </u>

% = 0.337 %

Mass = 35.97 u

<u>For second isotope, Argon-38: </u>

% = 0.063 %

Mass = 37.96 u

<u>For third isotope, Argon-40: </u>

% = 99.600 %

Mass = 39.96 u

Thus,  

Average\ atomic\ mass=\frac{0.337}{100}\times {35.97}+\frac{0.063}{100}\times {37.96}+\frac{99.600}{100}\times {39.96}=0.1212189+0.0239148+39.80016=39.9452937

<u>Average atomic mass = 39.95 u</u>

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Which example best describes a reflex action?
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Write the balanced COMPLETE ionic equation for the reaction when Na₂CO₃ and AgNO₃ are mixed in aqueous solution. If no reaction
alexdok [17]

Answer:

see explanation

Explanation:

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8 0
2 years ago
Identify the elements given the orbital diagrams listed below.​
Mrrafil [7]

Answer:

See explanation.

Explanation:

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2. 8 electrons. This is the same diagram as the one above.

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4 years ago
The first-order decay of radon has a half-life of 3.823 days. How many grams of radon decomposes after 5.55 days if the sample i
Leni [432]

Answer:

The mass of radon that decompose = 63. 4 g

Explanation:

R.R = P.E/(2ᵇ/ⁿ)

Where R.R = radioactive remain, P.E = parent element, b = Time, n = half life.

Where P.E = 100 g , b = 5.55 days, n = 3.823 days.

∴ R.R = 100/2^{5.55/3.823}

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Mass of radon that decompose = 100 - 36.63

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The mass of radon that decompose = 63. 4 g

8 0
3 years ago
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