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juin [17]
3 years ago
13

Calculate the average atomic mass of argon to two decimal places, given the following relative atomic masses and abundances of e

ach of the isotopes: argon-36 (35.97 u; 0.337%), argon-38 (37.96 u; 0.063%), and argon-40 (39.96 u; 99.600%)
Chemistry
1 answer:
user100 [1]3 years ago
4 0

Answer:

39.95 u

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})+(\frac {\%\ of\ the\ third\ isotope}{100}\times {Mass\ of\ the\ third\ isotope})

Given that:

<u>For first isotope, Argon-36: </u>

% = 0.337 %

Mass = 35.97 u

<u>For second isotope, Argon-38: </u>

% = 0.063 %

Mass = 37.96 u

<u>For third isotope, Argon-40: </u>

% = 99.600 %

Mass = 39.96 u

Thus,  

Average\ atomic\ mass=\frac{0.337}{100}\times {35.97}+\frac{0.063}{100}\times {37.96}+\frac{99.600}{100}\times {39.96}=0.1212189+0.0239148+39.80016=39.9452937

<u>Average atomic mass = 39.95 u</u>

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Step 5: Add both half-reactions and cancel what is repeated on both sides

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The balanced reaction is:

2 MnO₄⁻(aq) + 16 H⁺(aq) + 10 I⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 I₂(s)

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