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elena55 [62]
4 years ago
15

A gremlin is a tiny mythical creature often blamed for mechanical failures. Suppose for a moment that a shrewd physicist catches

one such gremlin and makes it work for her instead of against her. She determines that the gremlin can produce 24 milliwatts of power. How many gremlins are required to produce 24,000 megawatts of power?
Physics
1 answer:
pogonyaev4 years ago
7 0

Answer:

a billion (1,000,000,000) gremlins

Explanation:

since 1 milliwatt is 0.001 watt you'd need 1,000 gremlins to produce 24 watts

since 1 megawatt is 1000 watts you'd need 1,000*1,000 = 1,000,000 gremlins to produce 24 megawatts

to produce 24,000 megawatts you'd need to multiply that for another 1,000

so 1000*1000*1000 = 1,000,000,000

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A proton enters a magnetic field (B = 5.00 x 10^-2 T INTO THE PAGE) with
poizon [28]

Answer:

r = 1.16 m

Explanation:

It is given that,

Magnetic field, B=5.6\times 10^6\ m/s

Velocity of proton, v=5.6\times 10^6\ m/s

We need to find the radius (in m) of the  circular path the particle will follow when it is travelling within the  magnetic field. The radius followed by the proton is given by :

r=\dfrac{mv}{qB}

m is mass of proton, m=1.67\times 10^{-27}\ kg

So,

r=\dfrac{1.67\times 10^{-27}\times 5.6\times 10^6}{1.6\times 10^{-19}\times 5\times 10^{-2}}\\\\r=1.16\ m

So, the radius of circular path is 1.16 m.

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3 years ago
2 Calculate the distance from a srtaight wire where the magnetuc field is 0.66 T. the current in the wire is 4A and K = 2 x 10^-
nirvana33 [79]

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3 years ago
"True or False": Because action and reaction forces are equal in magnitude, they will produce the same acceleration in both obje
GREYUIT [131]

True im not 100% sure but I tried.

3 0
3 years ago
Why do concave lenses always form virtual images?
Licemer1 [7]

Answer:

The extension of the refracted rays will intersect at a point. This point is known as the focal point. Notice that a diverging lens such as this double concave lens does not really focus the incident light rays that are parallel to the principal axis; rather, it diverges these light rays.

Explanation:

5 0
3 years ago
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Sandy is whirling a ball attached to a string in a horizontal circle over his head. If Sandy doubles the speed of the ball, what
jeka57 [31]

The tension in the string B) It quadruples.

Explanation:

The ball is in uniform circular motion in a horizontal circle, so the tension in the string is providing the centripetal force that keeps the ball in circular motion. So we can write:

T= m\frac{v^2}{r}

where:

T is the tension in the string

m is the mass of the ball

v is the speed of the ball

r is the radius of the circle (the lenght of the string)

In this problem, we are told that the speed of the ball is doubled, so

v' = 2v

Substituting into the previous equation, we find the new tension in the string:

T' = m \frac{(2v)^2}{r}=4(m\frac{v^2}{r})=4T

Therefore, the tension in the string will quadruple.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

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