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olganol [36]
3 years ago
12

If you set up an experiment with two different independent variables, then the results would be​

Physics
1 answer:
valina [46]3 years ago
3 0

Answer: the same

Explanation:

You might be interested in
Agri-Chem's contract with Enerco specified a maximum of 90,000 cu.ft. X 103 per day for its complexes. However, curtailments are
zvonat [6]

Answer:

Caustic soda would be least affected by a gas curtailment

Explanation:

Let,

X1= ammonia

X2= ammonium phosphate

X3= ammonium nitrate

X4 = Urea

X5= hydro-fluoric acid

X6= Chlorine

X7= Caustic soda

X8= Vinyl chloride monomer.

Agri chem’s current natural gas usage

= (1200 × 8 + 540 × 10 + 490 × 12 + …)                  

= 85,680,000 cu. ft. per day  

When, the curtailment is 20%, availability is

= 0.8 X  85,680

= 68,554,000 cu. ft. per day

Therefore, the gas constant

= 8X1 + 10X2 + 12X3 + 12X4 + 7X5 + 18X6 + 20X7 + 14X8 ≤68,544

When, the curtailment is 40% availability is

= 0.6 X 85,680

= 51,408,000 cu. ft. per day

Constant = 8X1 + 10X2 + 12X3 + 12X4 + 7X5 + 18X6 + 20X7 + 14X8≤ 51,408

                     

7 0
3 years ago
During the latter part of your European vacation, you are hanging out at the beach at the gold coast of Spain. As you are laying
Jlenok [28]

Well, I guess you can come close, but you can't tell exactly.

It must be presumed that the seagull was flying through the air
when it "let fly" so to speak, so the jettisoned load of ballast
of which the bird unburdened itself had some initial horizontal
velocity.

That impact velocity of 98.5 m/s is actually the resultant of
the horizontal component ... unchanged since the package
was dispatched ... and the vertical component, which grew
all the way down in accordance with the behavior of gravity.

  98.5 m/s  =  √ [ (horizontal component)² + (vertical component)² ].

The vertical component is easy; that's (9.8 m/s²) x (drop time).
Since we're looking for the altitude of launch, we can use the
formula for 'free-fall distance' as a function of acceleration and
time:

             Height = (1/2) (acceleration) (time²) .

If the impact velocity were comprised solely of its vertical
component, then the solution to the problem would be a
piece-o-cake.

                  Time = (98.5 m/s) / (9.81 m/s²) = 10.04 seconds
whence
                 Height = (1/2) (9.81) (10.04)²

                            =   (4.905 m/s²) x (100.8 sec²)  =  494.43 meters.

As noted, this solution applies only if the gull were hovering with
no horizontal velocity, taking careful aim, and with malice in its
primitive brain, launching a remote attack on the rich American.

If the gull was flying at the time ... a reasonable assumption ... then
some part of the impact velocity was a horizontal component.  That
implies that the vertical component is something less than 98.5 m/s,
and that the attack was launched from an altitude less than 494 m.   

8 0
2 years ago
You want to see how your new belt buckle matches your new hat. Your eyes are 114 mm below the top of the hat and 800 mm above th
damaskus [11]

Answer:

x=0.057m

h=0.457m

Explanation:

From the question we are told that

Distance of eyes from the top of hat d_1=114mm

Distance of eyes from buckle  d_2=800mm

Generally position of mirror relative eyes x is mathematically given as

x=\frac{114}{2}

x=57mm

x=0.057m

Generally the height of the mirror h is mathematically given as

h=\frac{(Buckle\ below\ the\ hat)+(Buckle\ below\ the\ hat)}{2}

h=\frac{(114)+(800)}{2}

h=457mm

h=0.457m

7 0
2 years ago
The drawing shows four sheets of polarizing material, each with its transmission axis oriented differently. Light that is polari
Brrunno [24]

Answer:

Explanation:

When sheet A is removed

I_B=32\cos^230=24W/m^2\\\\I_C=24 \cos^260=6W/m^2\\\\I_D=6\cos^230=4.5W/m^2

When sheet B is removed

I_A=32\cos^20=32W/m^2\\\\I_C=24 \cos^290=0W/m^2\\\\I_D=0\cos^230=0W/m^2

When sheet C is removed

I_A=32\cos^20=32W/m^2\\\\I_D=32 \cos^230=24W/m^2\\\\I_B=24\cos^290=0W/m^2

When sheet D is removed

I_A=32\cos^20=32W/m^2\\\\I_B=32\cos^230=24W/m^2\\\\I_C=24\cos^260=6W/m^2

8 0
3 years ago
In a hydroelectric power plant, the shaft that connects the turbine to the generator has become inoperable. As a result, _____.
Lynna [10]
<span>Electricity will not be created.</span>
5 0
3 years ago
Read 2 more answers
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