The answer is a Mid-Ocean ridge.
Hi Pupil Here's Your Answer ::
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Pressure is defined as the force acting perpendicular on an unit area of the surface.
OR
The thrust per unit area is called Pressure.
let us see, on what factors the pressure depends?
Take a pin having a pointed end and a nail having blunt end. Press then against a cardboard by applying the same force. We find that the pin penetrates deep into the cardboard then the nail. In this case, force acting on two points of the cardboard is same but the area under the tip of the Pin is less than under the tip of the nail.
The effect of the forces of the scene magnitudes on the different area is different.
Conclusions : Pressure acting on the surface is inversely proportional to the area of the surface on which force acts.
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Hope this helps
Answer:
Atomic and molecular collision processes are the physical interactions of atoms and molecules when they are brought into close contact with each other and with electrons, protons, neutrons or ions. This includes energy-conserving elastic scattering and inelastic scattering.
Answer:
Grounded used to carry the current in the normal conditions. while on the other side grounding is refer to that safety wire that is connected to the earth and currently does not transmit through it.
As grounding wire is referred to as safety wire hence it carries current only in an emergency like a short circuit.
Explanation:
A grounded conductor is referred to as one of the wire that needed in an electric circuit. it is basically a neutral conductor. It used to carry the current in the normal conditions. while on the other side grounding is refer to that safety wire that is connected to the earth and currently does not transmit through it.
As grounding wire is referred to as safety wire hence it carries current only in an emergency like a short circuit.
Answer:
Explanation:
An impulse results in a change of momentum.
The impulse is the product of a force and a distance. This will be represented by the area under the curve
a) W = ½(4.00)(3.00) = 6.00 J
b) W = (11.0 - 4.00)(3.00) = 21.0 J
c) W = ½(17.0 - 11.0)(3.00) = 9.00 J
d) ASSUMING the speed at x = 0 is in the direction of applied force
½(3.00)(v₄²) = ½(3.00)(0.450²) + 6.00
v₄ = 2.05 m/s
½(3.00)(v₁₇²) = ½(3.00)(0.450²) + 6.00 + 21.0 + 9.00
v₁₇ = 4.92 m/s
If the initial speed is NOT in the direction of applied force, the final speed will be slightly less in both cases.
