Answer:
Draw the curved arrows showing a proton transfer reaction, and draw the products of that proton transfer. Do not include the Li counterion, and lone pairs are not required in the products and the question is hsown below:
Explanation:
The proton from water is abstracted by butyl carbanion and hydroxide ion is formed from water.
The reaction is shown below in the attachment.
Answer:
HEIGHT IS 6cm and the base is 10 cm
Explanation:
6H, 3S, and 12O
6 + 3 + 12 = 21
I believe 21 is your answer. I may be wrong, but I hope this helps anyways!
Answer:
Q = -14322.77 J
Explanation:
Given data:
Mass of water = 55.0 g
Initial temperature = 87.3°C
Final temperature = 25.0 °C
Heat given off = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 25.0 °C - 87.3°C
ΔT = - 62.3 °C
Q = 55.0 g×4.18 J/g.°C × - 62.3 °C
Q = -14322.77 J
Answer: true
explanation: