First we have to write balanced chemical equation:
CuSO₄.5H₂O + 4 NH₃ → [Cu(NH₃)₄]SO₄.H₂O + 4 H₂O
then calculate the molar mass of both CuSO₄.5H₂O and [Cu(NH₃)₄]SO₄.H₂O
MM CuSO₄.5H₂O = 249.612 g/mole
MM [Cu(NH₃)₄]SO₄.H₂O = 245.612 g/mole
from equation we see that:
1 mole CuSO₄.5H₂O ---gives ---> 1 mole [Cu(NH₃)₄]SO₄.H₂O
249.612 g ---gives ---> 245.612 g
? grams ---gives ---> 6 g complex
By cross multiplication we get that:
mass of CuSO₄.5H₂O required = 6.1 g
Answer:
pH of buffer solution is 7.0
Initial pH of Weak acid is 3.27
Final pH of weak acid is 3.07
Amount of NaOH added is 1ml
Explanation:
Titration is a process in which acid and base are introduced together until a neutral solution is achieved whose pH value is near to buffer solution which is 7.0, the pH value for acid is below 7 while pH value for base is above 7.
I think it might be A. i am not totally sure though
