Answer:
80 Joules.
Explanation:
Given that a 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of the hill with a speed of 8 m/s. During the slide, the work done by gravity is about ?
The parameters given are:
Mass M = 20 kg
Height h = 10 m
Velocity V = 8 m/s
The workdone by gravity will be equal to the total energy
At the bottom of the hill, the total energy will be equal to the maximum kinetic energy.
Maximum K.E = 1/2mv^2
K.E = 1/2 × 20 × 8
K.E = 80J
Therefore, the workdone by the gravity is equal to 80 Joules.
Answer:
The period is proportional to the square root of the length of the wire.
The period is independent of the suspended mass.
Explanation:
The period of a simple pendulum, in the small angle oscillation approximation, is given by
where
L is the length of the pendulum
g is the acceleration due to gravity
From the formula, we notice the following facts:
- The period is proportional to the square root of the length of the wire, L
- The period is independent of the suspended mass, m
So, these are the two correct statements.
For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as
Wt=1945.475J
<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>
Generally, the equation for work is mathematically given as
Wt=wac+Wc+Wba
Therefore
Wac=Pa(Vc-Va)=nR(Tc-Ta)
Wac=3(8.314*192)
Wac=4788.864J
Wcb=P1v1-p2v2/v-1
Wcb-3*8.34*108/0.4
Wcb=-6734.34J
Wab=0
In conclusion,
Wt=wac+Wc+Wba
Wt=4788.864J+0+(-6734.34J)
Wt=+1945.475J
Read more about work
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From Literature:
The amount of energy in the photons is given by this equation:
E = hf
where E = energy
h = Planck's constant = 6.63 * 10^-34 Joule seconds
f = frequency of the light, Hz
Given:
E= 3.00 eV and Planck's constant
To solve for the frequency, E = 3.00 eV
1 electronvolt = 1.60218 x 10^-19 Joules
3 * 1.60218 x 10^-19 Joules = 6.63 * 10^-34 Joule seconds * f
f = 7.25 x 10^14 /second or hertz
Therefore, the threshold frequency of the material is 7.25 x 10^14 Hertz.
Answer:
Opposition of passing a electric circuit
