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3 years ago

How much energy from the sun actually reaches the corn answer?

Physics

2 answers:

professor190 [17]3 years ago

7 0

Answer:

It depends upon the sunlight intensity known as ALBEDO, the amount of energy used by photosynthesis and the chemical composition of corn.

Explanation:

Albedo is a measure of the amount of light reflected from an object. Albedo is normally expressed as a decimal value representing the percentage of light reflected.

Photosynthesis, a biological process, uses the energy of sunlight to manufacture sugar, which serves as the universal food for life. Oxygen produced as a product of photosynthesis is released into the environment.

The formula for this reaction is:

6CO2 + 6H2O + sunlight energy → C6H12O6 + 6O2

• where CO2 represents carbon dioxide

• H2O represents water

• C6H12O6 represents the sugar molecules (carbohydrate)

• and O2 represents oxygen

Serhud [2]3 years ago

3 0

The energy from the sun that reaches the corn is about two billionths.

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A sinusoidal wave of angular frequency 1,203 rad/s and amplitude 3.1 mm is sent along a cord with linear density 3.9 g/m and ten

kobusy [5.1K]

Answer:

18.7842493212 W

Explanation:

T = Tension = 1871 N

$\mu$ = Linear density = 3.9 g/m

y = Amplitude = 3.1 mm

$\omega$ = Angular frequency = 1203 rad/s

Average rate of energy transfer is given by

$P=\dfrac{1}{2}\sqrt{T\mu}\omega^2y^2\\\Rightarrow P=\dfrac{1}{2}\sqrt{1871\times 3.9\times 10^{-3}}\times 1203^2\times (3.1\times 10^{-3})^2\\\Rightarrow P=18.7842493212\ W$

The average rate at which energy is transported by the wave to the opposite end of the cord is 18.7842493212 W

7 0

3 years ago

What is the gauge pressure of the water right at the point p, where the needle meets the wider chamber of the syringe? neglect t

Helen [10]

Missing details: figure of the problem is attached.

We can solve the exercise by using Poiseuille's law. It says that, for a fluid in laminar flow inside a closed pipe,

$\Delta P = \frac{8 \mu L Q}{\pi r^4}$

where:

$\Delta P$ is the pressure difference between the two ends

$\mu$ is viscosity of the fluid

L is the length of the pipe

$Q=Av$ is the volumetric flow rate, with $A=\pi r^2$ being the section of the tube and $v$ the velocity of the fluid

r is the radius of the pipe.

We can apply this law to the needle, and then calculating the pressure difference between point P and the end of the needle. For our problem, we have:

$\mu=0.001 Pa/s$ is the dynamic water viscosity at $20^{\circ}$

L=4.0 cm=0.04 m

$Q=Av=\pi r^2 v= \pi (1 \cdot 10^{-3}m)^2 \cdot 10 m/s =3.14 \cdot 10^{-5} m^3/s$

and r=1 mm=0.001 m

Using these data in the formula, we get:

$\Delta P = 3200 Pa$

However, this is the pressure difference between point P and the end of the needle. But the end of the needle is at atmosphere pressure, and therefore the gauge pressure (which has zero-reference against atmosphere pressure) at point P is exactly 3200 Pa.

8 0

3 years ago

A 0.10 kg mass is oscillating at a small angle from a light string of length 0.10 m.

cupoosta [38]

Answer:

tough

Explanation:

5 0

2 years ago

Un pendul este suspendat de un ax cu o tijă subțire foarte ușoară.

FromTheMoon [43]

Answer:

Explanation:

Given that a pendulum is suspended by a shaft with a very light thin rod.

Followed by the given information: m = 100 g, I = 0.5 m, g = 9.8 m / s²

We can determine the answer to these questions using angular kinematics.

Angular kinematics is just derived from linear kinematics but in different symbols, and expressions.

Here are the formulas for angular kinematics:

θ = ωt
∆w =
L [Angular momentum] = mvr [mass × velocity × radius]

A) What is the minimum speed required for the pendulum to traverse the complete circle?

We can use the formula v = √gL derived from

B) The same question if the pendulum is suspended with a wire?

C) What is the ratio of the two calculated speeds?

4 0

2 years ago

PLEASE HELP ASAP!!! 49 POINTS AND BRAINLIEST FOR BEST AND FASTEST ANSWER!!! (DO NOT ANSWER IF YOU DON'T KNOW, OR I WILL REPORT Y

Colt1911 [192]

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Seasons = the divisions of the year marked by specific weather patterns and daylight hours.

Hope this helps!

5 0

2 years ago

Read 2 more answers