Answer:
the second one
Explanation:
When a free positive charge q is accelerated by an electric field, such as shown in Figure 1, it is given kinetic energy. The process is analogous to an object being accelerated by a gravitational field. It is as if the charge is going down an electrical hill where its electric potential energy is converted to kinetic energy. Let us explore the work done on a charge q by the electric field in this process, so that we may develop a definition of electric potential energy.
The electrostatic or Coulomb force is conservative, which means that the work done on q is independent of the path taken. This is exactly analogous to the gravitational force in the absence of dissipative forces such as friction. When a force is conservative, it is possible to define a potential energy associated with the force, and it is usually easier to deal with the potential energy (because it depends only on position) than to calculate the work directly.
In this situation, both of the vehicles turn towards starboard.
By turning to the starboard, or right, side, the vehicles are able to avoid collision. Because waterways are not marked in a manner like roads are, it is necessary to place such conventions of turning in situations where vehicles approach one another head on. If a convention was not in place, the risk of collision would be many times greater. For example, the motorboat operator may turn left, while the PWC operator turns right, resulting in a collision.
C is the answer
D is impossible
A and B are false
Hope this helps!
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Explanation:
F=ma
m=3kg
F=7N
7=3a
a=7/3
acceleration=velocity/time taken
7/3=velocity/6
velocity=7/3×6/1
velocity=14ms-¹
Answer
given,
Initial speed of the car = 0 m/s
acceleration of car = 2.4 m/s²
Speed of the truck = 15.5 m/s
to car to overtake the truck distance travel by both should be same
distance traveled by the truck
d = 15.5 t
distance traveled by the car
d = u t + 1/2 gt ²
d = 0.5 x 9.8 t²
now, equating both the equations
15.5 t = 4.9 t²
t = 3.163 s
Time taken by car to overtake truck is 3.163 s
distance travel by the car = 15.5 x 3.163
d = 49 m
b) Speed of the automobile
using equation of motion
v = u + at
v = 0 + 2.4 x 3.163
v = 7.59 m/s
Speed of the automobile while crossing truck is equal to v = 7.59 m/s
