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Korvikt [17]
3 years ago
12

PLEASE HELP! I NEED ANSWER SOON

Physics
2 answers:
Serga [27]3 years ago
4 0

Answer:

5 and 3. I guess I am not very sure

Nikolay [14]3 years ago
4 0
The answers are 1,3,5
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A bungee jumper attains a speed of 30 m/s just as the bungee cord begins to stretch. If the period of stretch is 2 s while comin
Bogdan [553]

Answer:1.53g

Explanation:

average deceleration= ?

inial velocity: u=0

final velocity: v=30m/s

time: t=2seconds

The first law of kinematics :

v=u+at

find a the subject of the formula

a=v-u/ t

a=\frac{0-30} 2

a=-30/2

a=-15m/s^{2}

The deceleration about g(acceleration due to gravity) will be:

15/9.8

1.53g

4 0
3 years ago
All atoms of the same element must have the same number of
DIA [1.3K]
Since isotopes of any given element all contain the same number of protons,
3 0
4 years ago
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At the end of cylindrical rod of length l = 1 m and mass M = 1 kg rotating horizontaly along the vertical axis in its center wit
matrenka [14]

Answer:

w = 0.943 rad / s

Explanation:

For this problem we can use the law of conservation of angular momentum

       

Starting point. With the mouse in the center

            L₀ = I w₀

Where The moment of inertia (I) of a rod that rotates at one end is

         I = 1/3 M L²

Final point. When the mouse is at the end of the rod

          L_{f} = I w + m L² w

As the system is formed by the rod and the mouse, the forces during the movement are internal, therefore the angular momentum is conserved

        L₀ = L_{f}

        I w₀ = (I + m L²) w

        w = I / I + m L²) w₀

We substitute the moment of inertia

        w  = 1/3 M L² / (1/3 M + m) L²    w₀

        w = 1 / 3M / (M / 3 + m) w₀

We substitute the values

      w = 1/3 / (1/3 + 0.02) w₀

      w = 0.943 w₀

To finish the calculation the initial angular velocity value is needed, if we assume that this value is w₀ = 1 rad / s

        w = 0.943 rad / s

3 0
3 years ago
An iron anchor of density 7890.00 kg/m3 appears 299 N lighter in water than in air. (a) What is the volume of the anchor? (b) Ho
PtichkaEL [24]

Answer:

weigh is 2353.13 N

Explanation:

Given data

density = 7890.00 kg/m3

lighter =  299 N

to find out

the volume of the anchor and weigh in air

solution

from question we can say that

apparent weight = actual weight - buoyant force

we know weight = mg and buoyant force = water density × g

so volume of anchor is = actual weight - apparent weight / buoyant force

volume of anchor is = 299 / 1000 × 9.81

volume of anchor is = 0.0304791 m³

and

weight of anchor is mg

here mass m = density Fe g

density Fe = 7870 from table 14-1

so weight = 7870 × 0.0304791  × 9.81

weigh is 2353.13 N

7 0
4 years ago
Which statement demonstrates that ultraviolet (UV) rays are electromagnetic waves?
goldenfox [79]
The answer would probably be D
4 0
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