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3 years ago

7

Which statement accurately describes something that Yolanda can do as a part of her study?

2 answers:

Vikki [24]3 years ago

6 0

Thank you for posting your question here at brainly. Below is Yoland's study:

<span>Yolanda is studying two waves. The first wave has an amplitude of 2 m, and the second has an amplitude of 3 m.
</span>
I think the answer is "She can use constructive interference to generate a wave with an amplitude of 1.5 m."

d1i1m1o1n [39]3 years ago

6 0

Answer:

She can use constructive interference to generate a wave with an amplitude of 3.5 m.

Explanation:

finish the test and saw the right and wrong one

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If you blow across the open end of a soda bottle and produce a tone of 250 Hz, what will be the frequency of the next harmonic h

Naddika [18.5K]

Answer:

Generally, the lowest overtone for a pipe open at one end and closed would be at y / 4 where y represents lambda, the wavelength.

Since F (frequency) = c / y Speed/wavelength

F2 / F1 = y1 / y2 because c is the same in both cases

F2 = y1/y2 * F1

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3 years ago

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4 years ago

A student of weight 652 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude

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Answer:

Explanation:

Given

Weight of person $W=652\ N$

At highest point Magnitude of the normal force $F=585\ N$

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$F_{net}=F_{n}=$ Normal Force

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Negative sign shows force is in upward direction

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4 years ago

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3 years ago

Susan, driving north at 53 mphmph , and Shawn, driving east at 63 mphmph , are approaching an intersection. Part A What is Shawn

mafiozo [28]

Answer:

Shawn's speed relative to Susan's speed = 10 mph

Resultant velocity = 82.32 mph

Explanation:

The given data :-

i) Susan driving in north and speed of Susan is ( v₁ ) = 53 mph.

ii) Shawn driving in east and speed of Shawn is ( v₂ ) = 63 mph.

iii) The speed of both Susan and Shawn is relative to earth.

iv) The angle between Susan in north and Shawn in east is 90°.

We have to find Shawn's speed relative to Susan's speed.

v₂₁ = v₂ - v₁ = 63 - 53 = 10 mph

Resultant velocity,

$v = \sqrt{v_{2} ^{2}+ v_{1} ^{2} } =\sqrt{63^{2} +53^{2} }$

v = 82.32 mph

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3 years ago