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Sergeu [11.5K]
3 years ago
10

PLEASE HURRYY!!!!The diagram shows two balls released from a device at the same time. The ball on the left falls freely from res

t, and the ball on the right is launched horizontally Which best compares the vertical motion of the two balls?
A)Both balls have constant velocity and are acted on by gravity.
B)Both balls are acted on by gravity and are accelerating downward.
C)Both balls are pulled downward and have zero acceleration.
D)Both balls have zero acceleration and have constant velocity.
Physics
2 answers:
nasty-shy [4]3 years ago
6 0

Horizontal motion has no effect on vertical motion. Gravity has the same effect on both balls' vertical motion ... they both accelerate downward at 9.8 m/s^2. (B)

Even more interesting: A bullet fired horizontally and another bullet DROPPED from the gun's muzzle at the same time both hit the ground at the same time ... Maybe miles apart, but their vertical motions are identical.

LenaWriter [7]3 years ago
4 0

Answer:

i'm pretty sure its B but i may be wrong if you dont wanna take the chance wait for someone

Explanation:

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Answer:

demand (an amount) as a price from someone for a service rendered or goods supplied.

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How does the physical structure of a plant have<br> Large leaves help it survive?
elena-14-01-66 [18.8K]

The large leaves help it survive as they serve as the<u> organ for photosynthesis.</u>

Explanation:

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3 0
3 years ago
What is the MAIN cause of increased erosion, especially for soil?
egoroff_w [7]
I think it’s C. But I’m not completely sure.
7 0
3 years ago
Two loudspeakers emit identical sound waves along the x-axis. The sound at a point on the axis has maximum intensity when the sp
EleoNora [17]

The concept required to solve this problem is related to the wavelength.

The wavelength can be defined as the distance between two positive crests of a wave.

The waves are in phase, then the first distance is

\Delta x_1 = 20cm

And out of the phase when

\Delta x_2 = 30cm

Thus the wavelength is

\Delta x_2-\Delta x_1 = \frac{\lambda}{2}

Here,

\lambda =  Wavelength

If we rearrange the equation to find it, we will have

\lambda = 2 (\Delta x_2-\Delta x_1 )

\lambda= 2(30-20)

\lambda = 20cm

Therefore the wavelength of the sound is 20cm.

5 0
4 years ago
A particle's trajectory is described by x = (0.5t^3-2t^2) meters and y = (0.5t^2-2t), where time is in seconds. What is the part
mestny [16]

Differentiate the components of position to get the corresponding components of velocity :

v_x = \dfrac{\mathrm dx}{\mathrm dt} = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) t^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)t

v_y = \dfrac{\mathrm dy}{\mathrm dt} = \left(1\dfrac{\rm m}{\mathrm s^2}\right)t-2\dfrac{\rm m}{\rm s}

At <em>t</em> = 5.0 s, the particle has velocity

v_x = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) (5.0\,\mathrm s)^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s) = 17.5\dfrac{\rm m}{\rm s}

v_y = \left(1\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)-2\dfrac{\rm m}{\rm s} = 3.0\dfrac{\rm m}{\rm s}

The speed at this time is the magnitude of the velocity :

\sqrt{{v_x}^2 + {v_y}^2} \approx \boxed{17.8\dfrac{\rm m}{\rm s}}

The direction of motion at this time is the angle \theta that the velocity vector makes with the positive <em>x</em>-axis, such that

\tan(\theta) = \dfrac{3.0\frac{\rm m}{\rm s}}{17.5\frac{\rm m}{\rm s}} \implies \theta = \tan^{-1}\left(\dfrac{3.0}{17.5}\right) \approx \boxed{9.73^\circ}

4 0
2 years ago
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