Answer:
Energy converted = ![240000\,Joules = 240\, kJoules](https://tex.z-dn.net/?f=240000%5C%2CJoules%20%3D%20240%5C%2C%20kJoules)
Explanation:
Recall that Power is the rate at which energy is transferred therefore defined by the mathematical formula: ![Power\,=\,\frac{Energy\,transferred}{time}](https://tex.z-dn.net/?f=Power%5C%2C%3D%5C%2C%5Cfrac%7BEnergy%5C%2Ctransferred%7D%7Btime%7D)
Since the information on the power of the runner is given, as well as the time the energy conversion takes place, we can then use this equation to find how much energy is been converted. Notice that we just need to change the given time *10 minutes) into the appropriate units (seconds)to get the answer in SI units of energy (Joules). The conversion of 10 minutes into seconds is done by multiplying : 10 minutes * 60 seconds/minute = 600 seconds.
We use this then to find the energy converted by the runner:
![Power\,=\,\frac{Energy\,transferred}{time}\\400 \,W = \frac{E}{600\,sec} \\400 \,W * 600\,sec=E\\E=240000\,Joules = 240\, kJoules](https://tex.z-dn.net/?f=Power%5C%2C%3D%5C%2C%5Cfrac%7BEnergy%5C%2Ctransferred%7D%7Btime%7D%5C%5C400%20%5C%2CW%20%3D%20%5Cfrac%7BE%7D%7B600%5C%2Csec%7D%20%5C%5C400%20%5C%2CW%20%2A%20600%5C%2Csec%3DE%5C%5CE%3D240000%5C%2CJoules%20%3D%20240%5C%2C%20kJoules)
Pushing, pulling is the answer
pavement is defined as the surface of Road or sidewalk.
for example, the surface of Expressway.
There are two types of pavement.
rigid pavement which consists of one layer.
flexible pavement which consist of multiple layers.
While driving on roads of rural areas, if our right wheel moves off the pavement, we should always hold the steering wheel firmly and then take our foot off the pedal, then apply brake lightly until we are moving at a low speed.
if you run off the pavement, you should: turn the steering wheel quickly toward the road steer straight and slow down before attempting to return to the pavement steer straight ahead and speed up apply the brakes hard
To know more about pavement:
brainly.com/question/28456065
#SPJ4
Answer:
23. 4375 m
Explanation:
There are two parts of the rocket's motion
1 ) accelerating (assume it goes upto h1 height )
using motion equations upwards
![s = ut+\frac{1}{2}*a*t^{2} \\h_1=0+\frac{1}{2}*5*2.5^{2} \\=15.625 m](https://tex.z-dn.net/?f=s%20%3D%20ut%2B%5Cfrac%7B1%7D%7B2%7D%2Aa%2At%5E%7B2%7D%20%5C%5Ch_1%3D0%2B%5Cfrac%7B1%7D%7B2%7D%2A5%2A2.5%5E%7B2%7D%20%5C%5C%3D15.625%20m)
Lets find the velocity after 2.5 seconds (V1)
V = U +at
V1 = 0 +5*2.5 = 12.5 m/s
2) motion under gravity (assume it goes upto h2 height )
now there no acceleration from the rocket. it is now subjected to the gravity
using motion equations upwards (assuming g= 10m/s² downwards)
V²= U² +2as
0 = 12.5²+2*(-10)*h2
h2 = 7.8125 m
maximum height = h1 + h2
= 15.625 + 7.8125
= 23. 4375 m
The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time. According To a website on google