Answer:
330Ns
Explanation:
Given parameters:
Mass of the box = 5kg
Initial velocity = 0m/s
Force applied = 15N
Time = 22s
Unknown:
Impulse = ?
Final momentum = ?
Solution:
The impulse of the box can be determined using the expression below:
Impulse = Force x time
Impulse = 15 x 22 = 330Ns
The final momentum is the same as this impulse
The impulse and the final momentum is 330Ns
The resistance that one surface or object encounters when moving over another.
"a lubrication system that reduces friction”
Answer: well the time it takes to fall 100m is the same time it takes to travel 65m horizontally.
The time to fall vertically, t is sqrt(2d/g). [this comes from d = 1/2at^2]
so t = sqrt(2*100/9.8) = 4.52s.
The vertical speed at that time is g*t = 9.8*4.52 = 44.3m/s
The horizontal speed is the horizontal distance over the same 4.52s, = 65/4.52 = 14.4m/s.
so the final velocity is = sqrt(44.3^2 + 14.4^2) = 46.6m/s
Explanation: yes
The answer is no, the static charge would still be there.
To solve this problem it is necessary to apply the concepts related to simple harmonic movement.
The maximum speed from the simple harmonic motion is given as
Where,
K = Spring constant
m = mass
At this case m is a constant then
then the ratio is given by
According the statement,
Therefore the maximum speed becomes double: 2) It would increase by a factor of 2.